When light passes through a prism, the angle that the refracted ray makes relative to the incident ray is called the deviation angle δ , Fig. 32–64. Show that this angle is a minimum when the ray passes through the prism symmetrically, perpendicular to the bisector of the apex angle Φ , and show that the minimum deviation angle, δₘ , is related to the prism’s index of refraction n by
n = sin1/2 (Φ + δₘ ) / sinΦ/2
[Hint: For θ in radians, (d/dθ) (sin⁻¹ θ) = 1 √ (1 - θ²) .]
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