An LRC circuit in a radio receiver consists of L, R, and C in series, driven by an AC source at varying frequencies. At resonance, max power is dissipated. Find an approximate formula for the width of the resonance peak, Δf, which is the difference between the two frequencies where the power is half of its max value. Hint: Use the relationship at half max power:
1/2 P_max = V₀²R / [2(R² + (ωL - 1/ωC)²)]. For a sharp peak, assume R²C² ≪ 4LC.

• A. $\Delta f=\frac{R}{2 \pi L}$
• B. $\Delta f=\frac{R}{4 \pi L}$
• C. $\Delta f=\frac{R}{2 L}$
• D. $\Delta f=\frac{R}{\pi L}$