an-ac-power-source-with-a-variable-angular-frequency-is-connected-to-an-r-l-comb

Question

An AC power source with a variable angular frequency (ω) is connected to an R-L combination, as shown in the figure. Determine the expression of i) the current (I) in the circuit, ii) the voltage across the resistor, and iii) the voltage across the inductor as a function of ω. Hint: Use a phasor diagram.

AC circuit diagram showing a resistor (R) and inductor (L) with a voltage source E.

Accepted Answer

i) I= 5.0 V / √(L²ω² + R²)

ii) V_R = (5.0 V × R) / √(L²ω² + R²)

iii) V_L = (5.0 V × Lω) / √(L²ω² + R²)

Answer

i) I= 5.0 V / √(L²ω² + R²)

ii) V_R = (R) / √(L²ω² + R²)

iii) V_L = (5.0 V × Lω) / √(L²ω² + R²)

Answer

i) I= 5.0 V / (L²ω² + R²)

ii) V_R = (5.0 V × R) / √(L²ω² + R²)

iii) V_L = (5.0 V × Lω) / √(L²ω + R²)

Answer

i) I= 5.0 V / (L²ω² + R²)

ii) V_R = (5.0 V × R) / (L²ω² + R²)

iii) V_L = (5.0 V × Lω) / (L²ω² + R²)