the-figure-below-shows-two-horizontal-parallel-metal-plates-with-a-separation-di

Question

The figure below shows two horizontal parallel metal plates with a separation distance d between them. Determine the electric field vectors at points A, B and C if connecting these plates to a battery results in one plate acquiring a uniform charge density of σ₁ = +2σ₀ and the other plate obtaining a uniform charge density of σ₂ = -σ₀.

Accepted Answer

$\overrightarrow{E_{A}}$ = $\frac{\sigma_0}{2\varepsilon_0}$ ĵ , $\overrightarrow{E_{B}}$ = - $\frac{3\sigma_0}{2\varepsilon_0}$ ĵ , $\overrightarrow{E_{C}}$ = - $\frac{\sigma_0}{2\varepsilon_0}$ ĵ

Answer

$\overrightarrow{E_{A}}$ = $\frac{\sigma_0}{2\varepsilon_0}$ ĵ , $\overrightarrow{E_{B}}$ = $\frac{3\sigma_0}{2\varepsilon_0}$ ĵ , $\overrightarrow{E_{C}}$ = $\frac{\sigma_0}{2\varepsilon_0}$ ĵ

Answer

$\overrightarrow{E_{A}}$ = - $\frac{\sigma_0}{2\varepsilon_0}$ ĵ , $\overrightarrow{E_{B}}$ = - $\frac{\sigma_0}{2\varepsilon_0}$ ĵ , $\overrightarrow{E_{C}}$ = - $\frac{\sigma_0}{2\varepsilon_0}$ ĵ

Answer

$\overrightarrow{E_{A}}$ = - $\frac{\sigma_0}{2\varepsilon_0}$ ĵ , $\overrightarrow{E_{B}}$ = - $\frac{3\sigma_0}{2\varepsilon_0}$ ĵ , $\overrightarrow{E_{C}}$ = - $\frac{\sigma_0}{2\varepsilon_0}$ ĵ

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