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Ch. 32 - Light: Reflection and Refraction
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179Not the one you use?Change textbook
Chapter 31, Problem 79

When light passes through a prism, the angle that the refracted ray makes relative to the incident ray is called the deviation angle δ, Fig. 32–64. Show that this angle is a minimum when the ray passes through the prism symmetrically, perpendicular to the bisector of the apex angle Φ, and show that the minimum deviation angle, δm, is related to the prism’s index of refraction n by


n=sin12(ϕ+δm)sinϕ/2.n = \(\frac{\sin \frac{1}{2}\)(\(\phi\) + \(\delta\)_m)}{\(\sin\) \(\phi\)/2}.


[Hint: For θ in radians, (d/dθ)(sin1θ)=1/1θ2(d/d\(\theta\)) (\(\sin\)^{-1}\(\theta\)) = 1/\(\sqrt{1 - \theta^2}\).]

Verified step by step guidance
1
Step 1: Understand the geometry of the prism and the concept of deviation angle δ. The deviation angle is the angle between the incident ray and the refracted ray as light passes through the prism. The apex angle Φ is the angle at the vertex of the prism, and the ray passes symmetrically when it is perpendicular to the bisector of Φ.
Step 2: Use Snell's Law to relate the angles of incidence and refraction at the prism's surfaces. Snell's Law states that n₁ sinθ₁ = n₂ sinθ₂, where n₁ and n₂ are the indices of refraction of the two media, and θ₁ and θ₂ are the angles of incidence and refraction, respectively. For the prism, the index of refraction is n, and the surrounding medium is typically air (n₁ ≈ 1).
Step 3: Express the deviation angle δ in terms of the angles of incidence and refraction. The deviation angle δ is given by δ = θ₁ + θ₂ - Φ, where θ₁ and θ₂ are the angles of incidence and refraction at the two surfaces of the prism, and Φ is the apex angle.
Step 4: Minimize the deviation angle δ by considering symmetry. When the ray passes symmetrically through the prism, the angles of incidence and refraction are equal at both surfaces. Let θ₁ = θ₂ = θ. Substitute this into the expression for δ to simplify it: δₘ = 2θ - Φ.
Step 5: Relate the minimum deviation angle δₘ to the index of refraction n. Using Snell's Law and the symmetry condition, derive the relationship n = sin(1/2 (Φ + δₘ)) / sin(Φ/2). This involves substituting the symmetric angles into Snell's Law and simplifying the trigonometric expressions.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Refraction of Light

Refraction is the bending of light as it passes from one medium to another with a different density, which changes its speed. This phenomenon is governed by Snell's Law, which relates the angles of incidence and refraction to the indices of refraction of the two media. Understanding refraction is crucial for analyzing how light behaves when it encounters a prism.
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Index of Refraction

Deviation Angle

The deviation angle (δ) is defined as the angle between the incident ray and the refracted ray after passing through a prism. It is a key parameter in understanding how much the light path is altered by the prism. The minimum deviation occurs when the light passes symmetrically through the prism, which is essential for deriving the relationship between the prism's index of refraction and its geometry.
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Critical Angle

Index of Refraction

The index of refraction (n) is a dimensionless number that describes how much light slows down in a medium compared to its speed in a vacuum. It is a critical factor in determining how light bends when entering or exiting a prism. The relationship between the index of refraction, the prism's apex angle (Φ), and the minimum deviation angle (δₘ) is fundamental for understanding the optical properties of prisms.
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Related Practice
Textbook Question

Light from a laser (in air) strikes the exact center of one face of a solid glass cube (n = 1.40) at an angle θ relative to the normal. The refracted beam travels inside the glass until it strikes an adjacent face of the cube. The original angle of incidence θ is such that no light exits the cube where the beam strikes the second face. What is the maximum value θ can have?

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Textbook Question

A triangular prism made of crown glass (n = 1.52) with base angles of 26.0° is surrounded by air. If parallel rays are incident normally on its base as shown in Fig. 32–66, what is the angle Φ between the two emerging rays?

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Textbook Question

An object is placed 21 cm from a certain mirror. The image is half the height of the object, inverted, and real. How far is the image from the mirror, and what is the radius of curvature of the mirror?

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Textbook Question

A 1.80-m-tall person stands 4.20 m from a convex mirror and notices that he looks precisely half as tall as he does in a plane mirror placed at the same distance. What is the radius of curvature of the convex mirror? (Assume that θ ≈ θ .) [Hint: The viewing angle is half.]

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Textbook Question

We wish to determine the depth of a swimming pool filled with water by measuring the width (x = 5.20m) and then noting that the bottom edge of the pool is just visible at an angle of 13.0° above the horizontal as shown in Fig. 32–61. Calculate the depth of the pool.


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Textbook Question

The label on a laser says it produces light of wavelength 670 nm. The laser beam passes through a block of plastic for which n = 1.57. What is the wavelength of the light inside the plastic?

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