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25. Electric Potential
Equipotential Surfaces
5:13 minutes
Problem 23e
Textbook Question
Textbook QuestionCALC. A metal sphere with radius r_a is supported on an insulating stand at the center of a hollow, metal, spherical shell with radius r_b. There is charge +q on the inner sphere and charge -q on the outer spherical shell. (a) Calculate the potential V(r) for (i) r < r_a; (ii) r_a < r < r_b; (iii) r > r_b. (Hint: The net potential is the sum of the potentials due to the individual spheres.) Take V to be zero when r is infinite. (b) Show that the potential of the inner sphere with respect to the outer is V_ab=q/(4πϵ_0 ) (1/r_a -1/r_b). (c) Use E_r=-∂V/∂r=(-∂/∂r) (1/(4πϵ_0 ) q/r)=[1/(4πϵ_0 )](q/r^2) and the result from part (a) to show that the electric field at any point between the spheres has magnitude E(r)=[V_ab/(1/r_a -1/r_b )](1/r^2) (d) Use E_r = [1/(4πϵ_0 )](q/r^2) and the result from part (a) to find the electric field at a point outside the larger sphere at a distance r from the center, where r > r_b. (e) Suppose the charge on the outer sphere is not -q but a negative charge of different magnitude, say -Q. Show that the answers for parts (b) and (c) are the same as before but the answer for part (d) is different.
Verified step by step guidance
1
Identify the regions of interest based on the radius r: (i) r < r_a, (ii) r_a < r < r_b, and (iii) r > r_b. Use the principle of superposition to calculate the potential V(r) in each region by summing the contributions from the inner and outer spheres.
For r < r_a, only the potential due to the inner sphere affects this region as the outer shell's influence is nullified within it. Use the formula for the potential due to a point charge, V = kq/r, where k = 1/(4πϵ_0).
For r_a < r < r_b, the potential is constant throughout this region because the electric field inside a conductor is zero, which implies that the potential is the same at any point inside the shell. Calculate this constant potential using the potential at r_a due to both the inner sphere and the induced charge on the inner surface of the outer shell.
For r > r_b, the potential is due to both the inner sphere and the outer shell. Since the shell is grounded, its potential contribution at a distance r can be calculated using the formula for the potential outside a spherical shell.
To find the potential difference V_ab between the inner and outer spheres, use the expression V_ab = q/(4πϵ_0) (1/r_a - 1/r_b). This represents the work done per unit charge in moving a test charge from the outer sphere to the inner sphere without any acceleration.
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