Household wiring has sometimes used aluminium instead of copper.Typical copper wire used for home wiring in the U.S. has a diameter of 1.63 mm. What is the resistance of 125 m of this wire?
Ch. 25 - Electric Current and Resistance
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179Not the one you use?Change textbook
Chapter 24, Problem 98
Small changes in the length of an object can be measured using a strain gauge sensor, which is a wire that when undeformed has length ℓ₀, cross-sectional area A₀, and resistance R₀. This sensor is rigidly affixed to the object’s surface, aligning its length in the direction in which length changes are to be measured. As the object deforms, the length of the wire sensor changes by Δℓ, and the resulting change ΔR in the sensor’s resistance is measured. Assuming that as the solid wire is deformed to a length ℓ, its density and volume remain constant (only approximately valid), show that the strain ( = Δℓ / ℓ₀ ) of the wire sensor, and thus of the object to which it is attached, is approximately ΔR / 2R₀.
Verified step by step guidance1
Start by recalling the relationship between resistance and the physical properties of a wire. The resistance R of a wire is given by the formula: , where ρ is the resistivity, ℓ is the length, and A is the cross-sectional area of the wire.
Since the problem states that the volume and density of the wire remain constant during deformation, we can use the relationship for volume: . From this, we can express the new cross-sectional area A in terms of the original area A₀ and the change in length Δℓ: .
Substitute the expression for A into the resistance formula. The new resistance R becomes: . This shows that resistance depends on the square of the length of the wire.
Now, calculate the change in resistance ΔR due to the change in length Δℓ. Using the approximation for small changes, expand the square term: , where is the original resistance.
Finally, isolate the strain (Δℓ / ℓ₀) in terms of the change in resistance ΔR. From the previous step, we find: . This shows that the strain is approximately equal to ΔR / 2R₀, as required.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Strain
Strain is a measure of deformation representing the displacement between particles in a material body. It is defined as the change in length (Δℓ) divided by the original length (ℓ₀). Strain is a dimensionless quantity that indicates how much an object deforms under stress, and it is crucial for understanding how materials respond to external forces.
Resistance Change in Strain Gauges
In a strain gauge, the resistance of the wire changes as it deforms. This change in resistance (ΔR) is related to the strain experienced by the wire. The relationship between resistance and strain is derived from the physical properties of the wire, where the resistance is affected by changes in length and cross-sectional area, allowing for the measurement of strain through electrical resistance.
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Gauge Factor
The gauge factor is a dimensionless number that quantifies the sensitivity of a strain gauge. It is defined as the ratio of relative change in electrical resistance to the mechanical strain. For a typical metallic strain gauge, the gauge factor is approximately 2, which means that a small strain will produce a proportional change in resistance, facilitating the measurement of strain in materials.
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Related Practice
Textbook Question
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Textbook Question
Estimate how far can an average electron move along one of the connecting wires of a 750-W toaster during an alternating current cycle? The power cord has copper wires of diameter 1.7 mm and is plugged into a 60-Hz 120-V ac outlet. [Hint: For sinusoidal motion, Chapter 14, we saw that the maximum distance traveled from equilibrium (amplitude A) is proportional to the maximum (drift) speed (Eq. 14–9a). This maximum drift speed is related to the maximum current (Section 25–8), which is calculated as the first step here; see Chapter 14.]
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Textbook Question
Household wiring has sometimes used aluminium instead of copper. What would be the resistance of the same wire if it were made of aluminum?
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