Table of contents
- 0. Math Review31m
- 1. Intro to Physics Units1h 23m
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- Vectors, Scalars, & Displacement13m
- Average Velocity32m
- Intro to Acceleration7m
- Position-Time Graphs & Velocity26m
- Conceptual Problems with Position-Time Graphs22m
- Velocity-Time Graphs & Acceleration5m
- Calculating Displacement from Velocity-Time Graphs15m
- Conceptual Problems with Velocity-Time Graphs10m
- Calculating Change in Velocity from Acceleration-Time Graphs10m
- Graphing Position, Velocity, and Acceleration Graphs11m
- Kinematics Equations37m
- Vertical Motion and Free Fall19m
- Catch/Overtake Problems23m
- 3. Vectors2h 43m
- Review of Vectors vs. Scalars1m
- Introduction to Vectors7m
- Adding Vectors Graphically22m
- Vector Composition & Decomposition11m
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- Trig Review24m
- Unit Vectors15m
- Introduction to Dot Product (Scalar Product)12m
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- Intro to Cross Product (Vector Product)23m
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- 4. 2D Kinematics1h 42m
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- Magnetic Field Produced by Loops and Solenoids42m
- Toroidal Solenoids aka Toroids12m
- Biot-Savart Law (Calculus)18m
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- 30. Induction and Inductance3h 37m
- 31. Alternating Current2h 37m
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- 32. Electromagnetic Waves2h 14m
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- 34. Wave Optics1h 15m
- 35. Special Relativity2h 10m
4. 2D Kinematics
Intro to Motion in 2D: Position & Displacement
4:41 minutes
Problem 3b
Textbook Question
Textbook QuestionThe position of a squirrel running in a park is given by r = [(0.280 m/s)t + (0.0360 m/s2)t2]î + (0.0190 m/s3)t3ĵ. (b) At t = 5.00 s, how far is the squirrel from its initial position?
Verified step by step guidance
1
Identify the position function of the squirrel. The position vector is given by \( r = [(0.280 \, \text{m/s})t + (0.0360 \, \text{m/s}^2)t^2] \hat{i} + (0.0190 \, \text{m/s}^3)t^3 \hat{j} \).
Substitute the given time \( t = 5.00 \, \text{s} \) into the position function to find the position of the squirrel at that time. Calculate \( r(5.00) \) by plugging in \( t = 5.00 \, \text{s} \) into each component of the vector.
Calculate the initial position of the squirrel at \( t = 0 \, \text{s} \) by substituting \( t = 0 \) into the position function, resulting in \( r(0) \).
Determine the displacement vector \( \Delta r \) by subtracting the initial position vector \( r(0) \) from the position vector at \( t = 5.00 \, \text{s} \), i.e., \( \Delta r = r(5.00) - r(0) \).
Calculate the magnitude of the displacement vector \( \Delta r \) to find how far the squirrel is from its initial position. Use the formula for the magnitude of a vector: \( |\Delta r| = \sqrt{(\Delta x)^2 + (\Delta y)^2} \), where \( \Delta x \) and \( \Delta y \) are the components of the displacement vector.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Position Vector
A position vector describes the location of an object in space relative to a reference point, typically the origin of a coordinate system. In this case, the position of the squirrel is given as a function of time, incorporating both linear and nonlinear components. The vector notation indicates movement in two dimensions, represented by the unit vectors î and ĵ.
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Kinematics
Kinematics is the branch of mechanics that deals with the motion of objects without considering the forces that cause the motion. It involves analyzing position, velocity, and acceleration as functions of time. In this problem, the position function of the squirrel allows us to determine its displacement over a specified time interval.
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Displacement
Displacement is a vector quantity that represents the change in position of an object. It is calculated as the final position minus the initial position. In this scenario, to find how far the squirrel is from its initial position at t = 5.00 s, we evaluate the position vector at that time and compare it to the position at t = 0.
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