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Nice question

Hi there,

It's because it is being deprotonated by the Grignard reagent.

Deprotonation results in a negative charge because when the H atom leaves as a proton, it's electron remains with the atom to which it (H atom) was connected to. In this case, the N atom will keep the electron and therefore, it will get a negative charge.

I hope it helps. Let us know if you have more questions.

Hi there,

No, it's not a reducing sugar.

A reducing sugar is a sugar that can be oxidized by a weak oxidizing agent (e.g. Tollen's reagent). It is the C1 aldehyde that is oxidized to a carboxylic acid.

We don't have a C1 aldehyde here because it's already oxidized to a carboxylic acid. Therefore, it is a non reducing sugar.

I hope it helps. Let us know if you have more questions.