Now I want to talk about transition states a little bit more in-depth because earlier when I mentioned them, I mentioned them in very vague terms. I just said that it has to do with bonds being broken and destroyed at the same time. Okay? But it turns out that there's actually a very famous rule or postulate that was developed a while back to determine exactly what these transition states will look like depending on where they are in the free energy diagram. That is called the Hammond postulate. Alright? So what does the Hammond postulate say? It has to do with transition states. And the paraphrased version of it, the one that I think makes the most sense, is that transition states are going to most closely resemble, they're going to look the most like the species with the highest energy. Okay? So that means that remember that a transition state is always going to be your highest energy point on the graph, on the free energy diagram. And it's always going to relate some higher state of energy and some lower state of energy to each other. Okay? What your transition state is going to look like is going to be like the species that has the highest energy, whether that's the beginning or the end. Okay? And I'm going to show you guys what I mean by that in a second. Okay? If a transition state more closely resembles the reagents, we call that an early transition state. Okay? I'm just dyslexic today. Early. Okay? And if the transition state more resembles the products, then we call that a late transition state. Okay?
- 1. A Review of General Chemistry5h 5m
- Summary23m
- Intro to Organic Chemistry5m
- Atomic Structure16m
- Wave Function9m
- Molecular Orbitals17m
- Sigma and Pi Bonds9m
- Octet Rule12m
- Bonding Preferences12m
- Formal Charges6m
- Skeletal Structure14m
- Lewis Structure20m
- Condensed Structural Formula15m
- Degrees of Unsaturation15m
- Constitutional Isomers14m
- Resonance Structures46m
- Hybridization23m
- Molecular Geometry16m
- Electronegativity22m
- 2. Molecular Representations1h 14m
- 3. Acids and Bases2h 46m
- 4. Alkanes and Cycloalkanes4h 19m
- IUPAC Naming29m
- Alkyl Groups13m
- Naming Cycloalkanes10m
- Naming Bicyclic Compounds10m
- Naming Alkyl Halides7m
- Naming Alkenes3m
- Naming Alcohols8m
- Naming Amines15m
- Cis vs Trans21m
- Conformational Isomers13m
- Newman Projections14m
- Drawing Newman Projections16m
- Barrier To Rotation7m
- Ring Strain8m
- Axial vs Equatorial7m
- Cis vs Trans Conformations4m
- Equatorial Preference14m
- Chair Flip9m
- Calculating Energy Difference Between Chair Conformations17m
- A-Values17m
- Decalin7m
- 5. Chirality3h 39m
- Constitutional Isomers vs. Stereoisomers9m
- Chirality12m
- Test 1:Plane of Symmetry7m
- Test 2:Stereocenter Test17m
- R and S Configuration43m
- Enantiomers vs. Diastereomers13m
- Atropisomers9m
- Meso Compound12m
- Test 3:Disubstituted Cycloalkanes13m
- What is the Relationship Between Isomers?16m
- Fischer Projection10m
- R and S of Fischer Projections7m
- Optical Activity5m
- Enantiomeric Excess20m
- Calculations with Enantiomeric Percentages11m
- Non-Carbon Chiral Centers8m
- 6. Thermodynamics and Kinetics1h 22m
- 7. Substitution Reactions1h 48m
- 8. Elimination Reactions2h 30m
- 9. Alkenes and Alkynes2h 9m
- 10. Addition Reactions3h 18m
- Addition Reaction6m
- Markovnikov5m
- Hydrohalogenation6m
- Acid-Catalyzed Hydration17m
- Oxymercuration15m
- Hydroboration26m
- Hydrogenation6m
- Halogenation6m
- Halohydrin12m
- Carbene12m
- Epoxidation8m
- Epoxide Reactions9m
- Dihydroxylation8m
- Ozonolysis7m
- Ozonolysis Full Mechanism24m
- Oxidative Cleavage3m
- Alkyne Oxidative Cleavage6m
- Alkyne Hydrohalogenation3m
- Alkyne Halogenation2m
- Alkyne Hydration6m
- Alkyne Hydroboration2m
- 11. Radical Reactions1h 58m
- 12. Alcohols, Ethers, Epoxides and Thiols2h 42m
- Alcohol Nomenclature4m
- Naming Ethers6m
- Naming Epoxides18m
- Naming Thiols11m
- Alcohol Synthesis7m
- Leaving Group Conversions - Using HX11m
- Leaving Group Conversions - SOCl2 and PBr313m
- Leaving Group Conversions - Sulfonyl Chlorides7m
- Leaving Group Conversions Summary4m
- Williamson Ether Synthesis3m
- Making Ethers - Alkoxymercuration4m
- Making Ethers - Alcohol Condensation4m
- Making Ethers - Acid-Catalyzed Alkoxylation4m
- Making Ethers - Cumulative Practice10m
- Ether Cleavage8m
- Alcohol Protecting Groups3m
- t-Butyl Ether Protecting Groups5m
- Silyl Ether Protecting Groups10m
- Sharpless Epoxidation9m
- Thiol Reactions6m
- Sulfide Oxidation4m
- 13. Alcohols and Carbonyl Compounds2h 17m
- 14. Synthetic Techniques1h 26m
- 15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
- Purpose of Analytical Techniques5m
- Infrared Spectroscopy16m
- Infrared Spectroscopy Table31m
- IR Spect:Drawing Spectra40m
- IR Spect:Extra Practice26m
- NMR Spectroscopy10m
- 1H NMR:Number of Signals26m
- 1H NMR:Q-Test26m
- 1H NMR:E/Z Diastereoisomerism8m
- H NMR Table24m
- 1H NMR:Spin-Splitting (N + 1) Rule22m
- 1H NMR:Spin-Splitting Simple Tree Diagrams11m
- 1H NMR:Spin-Splitting Complex Tree Diagrams12m
- 1H NMR:Spin-Splitting Patterns8m
- NMR Integration18m
- NMR Practice14m
- Carbon NMR4m
- Structure Determination without Mass Spect47m
- Mass Spectrometry12m
- Mass Spect:Fragmentation28m
- Mass Spect:Isotopes27m
- 16. Conjugated Systems6h 13m
- Conjugation Chemistry13m
- Stability of Conjugated Intermediates4m
- Allylic Halogenation12m
- Reactions at the Allylic Position39m
- Conjugated Hydrohalogenation (1,2 vs 1,4 addition)26m
- Diels-Alder Reaction9m
- Diels-Alder Forming Bridged Products11m
- Diels-Alder Retrosynthesis8m
- Molecular Orbital Theory9m
- Drawing Atomic Orbitals6m
- Drawing Molecular Orbitals17m
- HOMO LUMO4m
- Orbital Diagram:3-atoms- Allylic Ions13m
- Orbital Diagram:4-atoms- 1,3-butadiene11m
- Orbital Diagram:5-atoms- Allylic Ions10m
- Orbital Diagram:6-atoms- 1,3,5-hexatriene13m
- Orbital Diagram:Excited States4m
- Pericyclic Reaction10m
- Thermal Cycloaddition Reactions26m
- Photochemical Cycloaddition Reactions26m
- Thermal Electrocyclic Reactions14m
- Photochemical Electrocyclic Reactions10m
- Cumulative Electrocyclic Problems25m
- Sigmatropic Rearrangement17m
- Cope Rearrangement9m
- Claisen Rearrangement15m
- 17. Ultraviolet Spectroscopy51m
- 18. Aromaticity2h 34m
- 19. Reactions of Aromatics: EAS and Beyond5h 1m
- Electrophilic Aromatic Substitution9m
- Benzene Reactions11m
- EAS:Halogenation Mechanism6m
- EAS:Nitration Mechanism9m
- EAS:Friedel-Crafts Alkylation Mechanism6m
- EAS:Friedel-Crafts Acylation Mechanism5m
- EAS:Any Carbocation Mechanism7m
- Electron Withdrawing Groups22m
- EAS:Ortho vs. Para Positions4m
- Acylation of Aniline9m
- Limitations of Friedel-Crafts Alkyation19m
- Advantages of Friedel-Crafts Acylation6m
- Blocking Groups - Sulfonic Acid12m
- EAS:Synergistic and Competitive Groups13m
- Side-Chain Halogenation6m
- Side-Chain Oxidation4m
- Reactions at Benzylic Positions31m
- Birch Reduction10m
- EAS:Sequence Groups4m
- EAS:Retrosynthesis29m
- Diazo Replacement Reactions6m
- Diazo Sequence Groups5m
- Diazo Retrosynthesis13m
- Nucleophilic Aromatic Substitution28m
- Benzyne16m
- 20. Phenols55m
- 21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
- Naming Aldehydes8m
- Naming Ketones7m
- Oxidizing and Reducing Agents9m
- Oxidation of Alcohols28m
- Ozonolysis7m
- DIBAL5m
- Alkyne Hydration9m
- Nucleophilic Addition8m
- Cyanohydrin11m
- Organometallics on Ketones19m
- Overview of Nucleophilic Addition of Solvents13m
- Hydrates6m
- Hemiacetal9m
- Acetal12m
- Acetal Protecting Group16m
- Thioacetal6m
- Imine vs Enamine15m
- Addition of Amine Derivatives5m
- Wolff Kishner Reduction7m
- Baeyer-Villiger Oxidation39m
- Acid Chloride to Ketone7m
- Nitrile to Ketone9m
- Wittig Reaction18m
- Ketone and Aldehyde Synthesis Reactions14m
- 22. Carboxylic Acid Derivatives: NAS2h 51m
- Carboxylic Acid Derivatives7m
- Naming Carboxylic Acids9m
- Diacid Nomenclature6m
- Naming Esters5m
- Naming Nitriles3m
- Acid Chloride Nomenclature5m
- Naming Anhydrides7m
- Naming Amides5m
- Nucleophilic Acyl Substitution18m
- Carboxylic Acid to Acid Chloride6m
- Fischer Esterification5m
- Acid-Catalyzed Ester Hydrolysis4m
- Saponification3m
- Transesterification5m
- Lactones, Lactams and Cyclization Reactions10m
- Carboxylation5m
- Decarboxylation Mechanism14m
- Review of Nitriles46m
- 23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
- 24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
- Tautomerization9m
- Tautomers of Dicarbonyl Compounds6m
- Enolate4m
- Acid-Catalyzed Alpha-Halogentation4m
- Base-Catalyzed Alpha-Halogentation3m
- Haloform Reaction8m
- Hell-Volhard-Zelinski Reaction3m
- Overview of Alpha-Alkylations and Acylations5m
- Enolate Alkylation and Acylation12m
- Enamine Alkylation and Acylation16m
- Beta-Dicarbonyl Synthesis Pathway7m
- Acetoacetic Ester Synthesis13m
- Malonic Ester Synthesis15m
- 25. Condensation Chemistry2h 9m
- 26. Amines1h 43m
- 27. Heterocycles2h 0m
- Nomenclature of Heterocycles15m
- Acid-Base Properties of Nitrogen Heterocycles10m
- Reactions of Pyrrole, Furan, and Thiophene13m
- Directing Effects in Substituted Pyrroles, Furans, and Thiophenes16m
- Addition Reactions of Furan8m
- EAS Reactions of Pyridine17m
- SNAr Reactions of Pyridine18m
- Side-Chain Reactions of Substituted Pyridines20m
- 28. Carbohydrates5h 53m
- Monosaccharide20m
- Monosaccharides - D and L Isomerism9m
- Monosaccharides - Drawing Fischer Projections18m
- Monosaccharides - Common Structures6m
- Monosaccharides - Forming Cyclic Hemiacetals12m
- Monosaccharides - Cyclization18m
- Monosaccharides - Haworth Projections13m
- Mutarotation11m
- Epimerization9m
- Monosaccharides - Aldose-Ketose Rearrangement8m
- Monosaccharides - Alkylation10m
- Monosaccharides - Acylation7m
- Glycoside6m
- Monosaccharides - N-Glycosides18m
- Monosaccharides - Reduction (Alditols)12m
- Monosaccharides - Weak Oxidation (Aldonic Acid)7m
- Reducing Sugars23m
- Monosaccharides - Strong Oxidation (Aldaric Acid)11m
- Monosaccharides - Oxidative Cleavage27m
- Monosaccharides - Osazones10m
- Monosaccharides - Kiliani-Fischer23m
- Monosaccharides - Wohl Degradation12m
- Monosaccharides - Ruff Degradation12m
- Disaccharide30m
- Polysaccharide11m
- 29. Amino Acids3h 20m
- Proteins and Amino Acids19m
- L and D Amino Acids14m
- Polar Amino Acids14m
- Amino Acid Chart18m
- Acid-Base Properties of Amino Acids33m
- Isoelectric Point14m
- Amino Acid Synthesis: HVZ Method12m
- Synthesis of Amino Acids: Acetamidomalonic Ester Synthesis16m
- Synthesis of Amino Acids: N-Phthalimidomalonic Ester Synthesis13m
- Synthesis of Amino Acids: Strecker Synthesis13m
- Reactions of Amino Acids: Esterification7m
- Reactions of Amino Acids: Acylation3m
- Reactions of Amino Acids: Hydrogenolysis6m
- Reactions of Amino Acids: Ninhydrin Test11m
- 30. Peptides and Proteins2h 42m
- Peptides12m
- Primary Protein Structure4m
- Secondary Protein Structure17m
- Tertiary Protein Structure11m
- Disulfide Bonds17m
- Quaternary Protein Structure10m
- Summary of Protein Structure7m
- Intro to Peptide Sequencing2m
- Peptide Sequencing: Partial Hydrolysis25m
- Peptide Sequencing: Partial Hydrolysis with Cyanogen Bromide7m
- Peptide Sequencing: Edman Degradation28m
- Merrifield Solid-Phase Peptide Synthesis18m
- 32. Lipids 2h 50m
- 34. Nucleic Acids1h 32m
- 35. Transition Metals5h 33m
- Electron Configuration of Elements45m
- Coordination Complexes20m
- Ligands24m
- Electron Counting10m
- The 18 and 16 Electron Rule13m
- Cross-Coupling General Reactions40m
- Heck Reaction40m
- Stille Reaction13m
- Suzuki Reaction25m
- Sonogashira Coupling Reaction17m
- Fukuyama Coupling Reaction15m
- Kumada Coupling Reaction13m
- Negishi Coupling Reaction16m
- Buchwald-Hartwig Amination Reaction19m
- Eglinton Reaction17m
Hammond Postulate - Online Tutor, Practice Problems & Exam Prep
The Hammond postulate explains that transition states in chemical reactions resemble the species with the highest energy, whether reactants or products. A transition state is the peak on a free energy diagram, linking higher and lower energy states. If it resembles the reactants, it's termed an early transition state; if it resembles the products, it's a late transition state. Understanding these concepts is crucial for grasping reaction mechanisms and energy profiles in organic chemistry.
The Hammond-Postulate more accurately describes what transition states look like.
Paraphrased version:
- “Transition states most closely resemble the species with the highest energy”
Defining the Hammond Postulate.
Video transcript
- Early transition state = Resembles reagents
- Late transition state = Resembles products
Chlorination explains the Hammond Postulate.
Video transcript
So in this case, notice that we have a 2 step reaction here. Okay? This is called radical chlorination by the way. What I'm doing is I'm taking an alkane and I'm adding diatomic chlorine and I'm breaking some bonds. What I get at the end is an alkyl halide and a strong acid, HCl. What we see is that overall, the delta g of this reaction is spontaneous. Okay? So we know this is going to be a spontaneous reaction. Okay? But what we don't know is what this transition state is going to look like up here? Okay? Is that going to look more like the products, which I mean more like the reagents, which would just be a regular alkane with a chlorine radical? Okay? Which by the way, you don't need to know this mechanism yet. I'm just explaining the steps. Or is it going to look more like the intermediate here, which happens to be the radical on the alkane and then the HCl together? Okay? Well, the way we would determine this is by looking at the energy state of the reagent and the energy state of the intermediate. Basically, the 2 things on different sides of the transition state. And I would ask myself which one has the higher energy. Whichever one has the higher energy is going to be the one that is going to look more like the transition state or the transition state is going to look more alike. Okay? So what I'm going to do is I'm going to do this first example as a worked example together and then I want you guys to do the next one on your own. Alright? So we already said which one has the higher energy? Is it the reagents or is it the intermediate? It looks like it's the reagents. Okay? So the one with the higher energy is reagents. Let's circle that. Okay? So since the transition state is gonna basically Which one has the higher energy? The reagents. So the transition state is going to look more like the species with the highest energy. So it's going to look more like the reagents. Okay? Since it looks more like the reagents, that means I'm going to have an early transition state. Okay? Now, this is what the transition state would look like without Hammond's postulate. If I wasn't using Hammond's postulate, I would just say, okay, I have an alkyl group that still is partially bonded to an H, but then that H is partially bonded to a Cl. And they're all perfectly breaking and perfectly making at the same time, so they have equal distances from each other. Okay? So that would be what my transition state, I would think, would look like without Hammond's postulate. But we know that Hammond's postulate exists. Hammond's postulate tells me that it's actually not going to look like this. Instead, what it's going to look like is that it's gonna look more like the thing with the highest energy. The highest energy is this. So that means that notice that if it was perfectly just starting off as the reagent, what I would have is a CH2 with a full bond to H and then the H having no bond to the Cl. That's the reagent. Okay? If I was completely at the intermediate side, what I would have is a CH3 with no bond to the H and then the H with a full bond to the Cl. So see how this is kind of like an action sequence where my H is slowly going this way and it's basically moving closer and closer to the chlorine until it gets here. And it is fully possessed by the chlorine. Okay? This transition state shows that middle step of well, that's what the hydrogen would look like right in the middle when it's like at the highest point. Okay? But it turns out that, like I said, it's not going to look like that since this is an early transition state, it's going to look more like this and less like the intermediate. So what I would expect the transition state to look like is actually more like this where I have a dotted line to an H that's pretty close by and then I have a really, really far dotted line to the Cl. Why is that? Because this transition Okay? So what that means is it should look more like the H is still attached to the alkyl group and less like the H is attached to the Cl because the Cl doesn't happen until later and that's not the highest energy step. Does that kind of make sense guys? So what I'm trying to do is I'm trying to get you guys to draw transition states based on the Hammond postulate. And all you do is just say whichever one has the highest energy, that's the one that my transition state's going to look more like. Okay? So I hope that you guys can see now that the distance between my alkyl group and my H is way shorter than the distance between my H and Cl. Why? Because this is an early transition state, so it happens a lot closer to the alkyl group. So now what I want you guys to do is go ahead and draw the transition state for the radical bromination all on your own by understanding and dissecting this free energy diagram. So go for it.
Bromination explains the Hammond Postulate.
Video transcript
All right. So as you guys can see, this reaction is very similar to the chlorination. What we have for our reagents is that the H is fully attached to the alkyl group. Okay? What we have for our intermediate is that the H is fully attached to the bromine. So we know this is going to be another example where in our transition state, my H is going to be somewhere between the alkyl group and the bromine. Okay? But we know that it's not going to be perfectly in the middle because Hammond's postulate states that it's usually not going to be right in the middle. It's always going to look more like one or the other side. Okay? So now we just have to figure out which side does it look more like. So, what I do is I compare the energy level of my reagents and the energy level of my intermediate. Which of these is higher? The energy level of my intermediate this time is higher. So that means that my transition state is going to look more like the intermediate or more like the products. So this is going to be a late transition state. Okay? A late transition state means that it has to look more like this where the H is bonded to the Br and less like the H is bonded to the alkyl group. So the way this transition state should have been drawn is like this where I have a really, really, really far bond to the H. So it's almost completely gone. The H is almost completely gone and then a really short bond to the Br. So what you can see is that the transition state looks almost completely like this. The only difference is that I still just have to use a dotted line to show that it's all happening in one step. Alright? Does that make sense, guys? One more thing, because of the fact that there's too many bonds here, I should have a negative charge in my transition state. So for both of these, I forgot to include that, there should be a partial negative here and partial negative here. So sometimes what happens is that they'll just draw partial negatives on all the species. Okay. And that's fine too. That just shows that there's a negative charge that's being distributed throughout. Why would there be a negative charge? Do you guys want to think about that for a second? Because of the fact that hydrogen doesn't like to have 2 bonds. Okay? So that means that this hydrogen right now has one more bond than it likes to have because they're kind of both being formed and both being destroyed at the same time. So we have an extra bond that we need to distribute that negative charge for. So that's why I put those little delta negatives. Okay? Lowercase delta. So I hope you guys can see the difference in these transition states and hopefully, Hammond's postulate doesn't have to be really hard for you guys. I think if you just remember, it looks like the highest energy-like species that's going to really help you guys be able to draw these accurately. Alright? So let me know if you have any questions. Let's move on.
Do you want more practice?
More setsHere’s what students ask on this topic:
What is the Hammond postulate in organic chemistry?
The Hammond postulate states that the transition state of a chemical reaction resembles the species (reactants or products) with the highest energy. This means that if the transition state is closer in energy to the reactants, it will resemble the reactants more closely, and if it is closer in energy to the products, it will resemble the products more closely. This concept helps in understanding the nature of the transition state and predicting the reaction mechanism. The transition state is the highest energy point on a free energy diagram, linking higher and lower energy states.
How does the Hammond postulate help in understanding reaction mechanisms?
The Hammond postulate aids in understanding reaction mechanisms by providing insight into the nature of the transition state. By knowing whether the transition state resembles the reactants or products, chemists can infer details about the reaction pathway. For example, an early transition state (resembling reactants) suggests that the reaction proceeds quickly from reactants to transition state, while a late transition state (resembling products) indicates that the reaction has a higher activation energy and proceeds more slowly. This information is crucial for predicting reaction rates and designing efficient chemical processes.
What is the difference between an early and a late transition state according to the Hammond postulate?
According to the Hammond postulate, an early transition state resembles the reactants more closely and occurs when the transition state is closer in energy to the reactants. This typically happens in exothermic reactions where the energy barrier is lower. Conversely, a late transition state resembles the products more closely and occurs when the transition state is closer in energy to the products. This is common in endothermic reactions where the energy barrier is higher. Understanding whether a transition state is early or late helps in predicting the reaction's energy profile and mechanism.
Why is the transition state the highest energy point on a free energy diagram?
The transition state is the highest energy point on a free energy diagram because it represents the point at which the reactants are in the process of being converted into products. At this stage, bonds are being broken and formed, requiring a significant amount of energy. This energy peak is necessary to overcome the activation energy barrier of the reaction. Once the transition state is reached, the system can proceed to form the products, which are at a lower energy level. The height of this peak determines the reaction rate and is a critical factor in reaction kinetics.
How can the Hammond postulate be applied to predict the outcome of a chemical reaction?
The Hammond postulate can be applied to predict the outcome of a chemical reaction by analyzing the energy levels of the reactants and products. By determining whether the transition state is early or late, chemists can infer the reaction pathway and the relative stability of intermediates. For instance, in an exothermic reaction with an early transition state, the products are likely to form quickly and be more stable. In an endothermic reaction with a late transition state, the reaction may proceed more slowly, and the products may be less stable. This predictive power is valuable for designing reactions and optimizing conditions.
Your Organic Chemistry tutors
- Deuterium (D) is the hydrogen isotope of mass number 2, with a proton and a neutron in its nucleus. The chemis...
- In the presence of a small amount of bromine, cyclohexene undergoes the following light-promoted reaction: Cy...
- Assuming that ∆H° = -15kcal/mol for the reaction in Assessment 5.31(b), show the transition state for the forw...
- (•) For each of the following acid–base reactions, (iv) draw the transition state, paying close attention to ...
- Is the structure of the transition state in the following reaction coordinate diagrams more similar to the st...
- Which is the most likely transition state for the reactions shown? Explain your answer. [Note the difference i...
- Which would you expect to be more selective for carbocation formation, the electrophilic addition of HF or HBr...
- Show the transition state of each step of the following alkene addition reaction. Be sure to indicate whether ...
- The most stable intermediate forms first. Explain this statement by showing a reaction coordinate diagram for ...
- Deuterium (D) is the hydrogen isotope of mass number 2, with a proton and a neutron in its nucleus. The chemis...
- Using the bond-dissociation energies in Table 5.6, <IMAGE>(b) Will the transition state be reactant-like...