In this video, we're going to discuss the most famous pericyclic reaction in organic chemistry and that's called the Diels-Alder reaction. The Diels-Alder reaction is a heat-catalyzed reversible pericyclic reaction between 2 different molecules that we're going to go into more depth on. Now the one thing in common between all Diels-Alder reactions is that they're always going to yield a 6-membered ring as their product. So you always know that you're going to create one new ring through the formation of a reaction. We need 2 components plus heat to make this happen. We're going to need 1, a 1,3-diene. 2, we're going to need a dienophile. Now I recognize that these are terms that you're probably not that familiar with, so let's really just dive into what that is. First of all, a 1,3-diene is pretty simple. It sounds like exactly what you're thinking. It's a diene that is at the 1 and the 3 position. Basically, another way to say it is that it just has to be a conjugated diene because if it's not 1,3, let's say that we used a 1,4-diene, then that would no longer be a conjugated diene. We would actually call that an isolated diene because now the double bonds wouldn't be next to each other. They would have a space in between. So you can't use a 1,4-diene. That's isolated. You need to use a conjugated diene. Let's look at some examples. This first one's pretty easy. That looks like a typical diene. You can have any other R groups. The important thing is that you at least have that 1,3-diene. Here you see that we actually have a cyclic in the middle. We have a cyclic 1,3-diene because one of them starts at the 1 and one of them starts at the 3. You might be wondering, Johnny, why are you using those specific atoms to count as 1,3? It doesn't matter where you start as long as you have diene starting basically 2 carbons away from each other. At the 1 and at the 3, you have 2 diene, 2 double bonds starting. So that's another diene. And then here we have another example of a 1,3-diene. So I'm just trying to show you guys how 1,3-dienes can come in all shapes and sizes. We're just caring about the fact that they're conjugated to each other. Now what's a dienophile? Well, by definition, the word phile means lover. So a dienophile would be a molecule that loves dienes. So dienophiles are actually really easy. All they are is that they are alkenes or alkynes. That's it. It's really that easy. A dienophile could just be a simple cyclohexene. Just having that double bond there is a dienophile. Now notice that this next molecule here has 2 double bonds. Which part of it do you think is the dienophile? Well, I said in the definition it has to be an alkene or an alkyne, So this is actually the dienophile, nothing else. The carbonyl doesn't count. Check this out. That's weird. Did I make a mistake? Did I drag the wrong molecule, the same molecule to this box? No, I didn't because it turns out that dienes have alkenes in them, right? So that means both of these double bonds can act as dienophiles. That means you can sometimes see dimerization taking place with these reactions where one molecule reacts as the diene and the other reacts as the dienophile and they react together to form a dimer or something that there's 2 of now attached to each other. That's something we're going to need to be aware of. Here's our last example. Triple bonds have pi bonds in them, so this can also be a dienophile. Pretty simple so far. We know that we need a diene, a 1,3-diene. We need a dienophile. We need heat because I told you it's a heat-catalyzed reaction. But it turns out there's few more technicalities you have to go over before you're ready to draw these. So one is that your 1,3-diene has to be in a certain shape. You can't just use any one 1,3-diene. The 1,3-diene has for the mechanism to work, you're going to need to have your 1,3-diene rotated into what's called the S-cis or sigma-cis conformation. Now remember from organic chemistry 1 that sigma bonds are able to freely rotate as much as they want. Meaning that just because it's in that position now doesn't mean it will always stay there. We have to make sure that at least it's able to rotate into the S-cis conformation momentarily. Why? Because if you were to draw a dotted line along the single bond or the sigma bond, what you would find is that your R groups are on opposite sides. That's what we call S-trans because your sigma bond is rotated in such a way that they're on opposite sides. Now if we were to rotate that sigma bond, what we would find is that now when we draw that same line, now they're on the same side. This is what we would call S-cis. This is the way we need it to be rotated. This would be a big no-no. You can't start off like that. In order to begin your Diels-Alder reaction, you must rotate it first into the S-cis and then you can proceed. Not that bad. Now let's look at the general mechanism. The general mechanism is going to be an S-cis diene. Specifically, S-cis 1, let's get it right, 1,3-diene, right? With a dienophile. Remember I told you guys that a dienophile can be any alkene or alkyne. This molecule right here is a perfect dienophile because it's just got that double bond. The cyclization reaction is a 3-membered or 3-arrow reaction where you would get the dienophile initiating because remember it's like the lover of the diene. It just wants to attack it. So I would go ahead and I would attack one of the edges. But if I make a bond, I have to break a bond because I'm in violation of an octet if I don't. So then this double bond is going to make a new double bond here. Once again, make a bond, break a bond. I'm going to need to break that last diene, so this one comes over and attaches to the other side of the double bond. This is going to form 2 new sigma bonds. This forms a new single bond here and this forms a new single bond here and then this arrow that's going in between the dienes forms a new pi bond here. Our final product has 2 new bonds and a double bond. As you can see, I now have a 6-membered cyclic product. Cool so far? That's the general mechanism. Now, there are a lot you could get a problem that's just that easy. But Diels-Alder can get a little bit more complicated as I'll show you guys. Now I'm going to start layering on the complications. The first of which being, it's pretty straightforward, that the stereochemistry of all substituents must be retained. You have to identify the stereochemistry of your dienophile and your diene so that when you react this together and make a ring, that the stereochemistry is preserved. Check out this first Diels-Alder. We have a 1,3-diene and a dienophile. But notice that my R groups on this dienophile are in a cis position. This would be a cis alkene. Remember, double bonds don't twist, so it's always going to be cis. It can't be trans. The way we can tell it's cis is if we were to draw that dotted line or fence that I like to use. They're both on one side of it. Well, when we react this product, we're going to we're going to draw our arrows. When we react this product, you need to make sure that your R groups remain cis to each other. They have to remain on the same side of the ring. Now did I have to face them up? No. I could've also faced them down. The important part is that they're both facing the same exact direction. It wouldn't make sense if I put 1 R up and 1 R down because that would look like trans and that's not what I began with, right? Awesome. That's pretty straightforward. In the same way, if I began with a trans double bond, as you can see this one's different, then I'm going to get a pair of enantiomers because I'm just going to take myself out of the screen because as you can see, now I'm going to get trans products but there's 2 different ways that those trans products could orient each other. I could get R1 in the front, but I could also get R2 in the front just depending on how the attack works. In this case, I would have to draw a pair of enantiomers because I have 2 different trans products that are possible. This is just really basic stuff that you have to make sure you get right. And make sure you pay attention to the stereochemistry in order to get the full credit for this question. Okay? So pretty easy so far. But that's not it. There's a few more complications with Diels-Alder. So let's go ahead and move on to a few more concepts.
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Diels-Alder Reaction: Study with Video Lessons, Practice Problems & Examples
The Diels-Alder reaction is a key pericyclic reaction in organic chemistry, producing a six-membered ring from a conjugated 1,3-diene and a dienophile, typically an alkene or alkyne, under heat. The diene must adopt the s-cis conformation for the reaction to proceed. Stereochemistry is crucial; substituents on the dienophile must retain their configuration in the product. This reaction exemplifies concerted mechanisms, where bonds are formed and broken simultaneously, leading to new sigma and pi bonds in the cyclic product.
The Diels-Alder reaction is a heat-catalyzed, reversible pericylic reaction between a conjugated 1,3-diene and a dienophile.
General Features
Video transcript
Do you want more practice?
More setsThe Diels-Alder reaction is a [4+2] cycloaddition reaction that always produces a six-membered ring and sometimes produces a bicyclic compound. It is a pericyclic reaction between an electron-rich conjugated diene and an electron-poor dienophile.
Diels-Alder reaction and mechanism
The Diels-Alder is a thermocyclic reaction between a conjugated diene and a dienophile. There are three arrows, and the important thing to remember is that they trace a circle in the same direction; that is, they either go clockwise or counterclockwise. I suggest picking one and sticking to it! Let’s check out the general mechanism
1,3-butadiene and ethene
Let’s look at this mechanism starting from the pi bond between carbons three and four. The pi bond attacks carbon 5 on the dienophile, which causes the pi bond between carbons five and 6 to attack carbon 1 in the dienophile, which causes the electrons in the pi bond between carbons 1 and 2 to move between carbons 2 and 3.
That’s a long-winded way to say that we end up with a six membered ring and our sigma bond between carbons 2 and 3 gets a pi bond. Of course, there is a transition state, so let’s see what it looks like:
Aromatic transition state
The transition state of the Diels-Alder reaction is 1) planar, 2) cyclic, 3) fully conjugated, and 4) has 6 pi electrons, which satisfies Huckel’s rule. That makes it aromatic!
Adding complexity
Bridged molecules
In our simplest Diels-Alder, we form a six-membered ring. But what happens when our diene is already a six-membered ring like 1,3-hexadiene? We actually form a bicyclic compound! The diene atoms that don’t actually participate in the form a bridge like this:
Building bridges
Notice that we end up with a new six-membered ring and our original one basically folds out of the way. The red lines in the product are the new bonds formed from the red arrows.
Substituents
Ignoring stereochemistry for now, let’s check out how substituents affect the product. Let’s say we have 2-ethyl-3-methylcyclohexa-1,3-diene reacting with 1-butene. Depending on the molecules’ orientations, we can end up with two different products!
Regiospecificity
Notice that in the first reaction, the blue ethyl group is near the green methyl group but it’s different in the second reaction; the blue ethyl group is near the green ethyl group in the second reaction.
EDGs and EWGs
Electron-donating groups (EDGs) and electron-withdrawing groups (EWGs) are often found in Diels-Alder reactions. EDGs (e.g. amines and alkoxy groups) are generally found on the diene, and EWGs (e.g. carbonyls and anhydrides) are generally found on the dienophile.
EDGs and EWGs
Of course, just like the ethyl group in the previous example, we could have two different molecules here. This is just to show there the groups are generally placed.
Heteroatoms and alkynes
Every once in a while you might come across an alkyne as a dienophile or a heteroatom in your diene. Let’s take a look at the reaction mechanism between a furan and ethyne as the dienophile:
Furan and acetylene
Notice that it’s not very different even though there’s a triple bond and oxygen? All we did was kick the oxygen up to the bridge and react with only one of the pi bonds in the ethyne; the other pi bond stayed there between carbons 5 and 6!
Endo and exo
Diels-Alder reactions can produce diastereomers called endo and exo products. If all groups are on the same side of the newly formed ring, it’s an endo product; if substituents are on opposite sides of the ring, it’s an exo product! Check out this image to see what I mean:
Endo and exo
Here’s what students ask on this topic:
What is the Diels-Alder reaction and why is it important in organic chemistry?
The Diels-Alder reaction is a pericyclic reaction that forms a six-membered ring by reacting a conjugated 1,3-diene with a dienophile (typically an alkene or alkyne) under heat. This reaction is crucial in organic chemistry because it allows for the efficient synthesis of complex cyclic structures, which are common in natural products and pharmaceuticals. The reaction proceeds via a concerted mechanism, meaning bonds are formed and broken simultaneously, leading to new sigma and pi bonds in the cyclic product. Its ability to form stereospecific products makes it a valuable tool for chemists.
What are the key components required for a Diels-Alder reaction?
The key components required for a Diels-Alder reaction are a conjugated 1,3-diene and a dienophile. The diene must be in the s-cis conformation for the reaction to proceed. The dienophile is typically an alkene or alkyne. Additionally, heat is required to catalyze the reaction. The reaction results in the formation of a six-membered ring, with the stereochemistry of substituents on the dienophile being retained in the product.
How does the stereochemistry of the dienophile affect the Diels-Alder reaction product?
The stereochemistry of the dienophile is crucial in the Diels-Alder reaction because it is retained in the product. If the dienophile has cis substituents, the resulting six-membered ring will also have those substituents in a cis configuration. Conversely, if the dienophile has trans substituents, the product will have those substituents in a trans configuration. This retention of stereochemistry is important for the synthesis of specific stereoisomers, which can have different chemical and biological properties.
What is the role of the s-cis conformation in the Diels-Alder reaction?
The s-cis conformation of the 1,3-diene is essential for the Diels-Alder reaction to occur. In this conformation, the diene's double bonds are positioned such that they can effectively overlap with the dienophile's π system, facilitating the concerted mechanism of the reaction. If the diene is in the s-trans conformation, the necessary orbital overlap cannot occur, and the reaction will not proceed. Therefore, ensuring the diene can adopt the s-cis conformation is a critical aspect of the reaction setup.
Can you explain the general mechanism of the Diels-Alder reaction?
The general mechanism of the Diels-Alder reaction involves a concerted process where a conjugated 1,3-diene in the s-cis conformation reacts with a dienophile. The reaction proceeds through a three-arrow mechanism: the π electrons of the diene and dienophile interact to form two new sigma bonds and one new π bond, resulting in a six-membered ring. This concerted mechanism ensures that bonds are formed and broken simultaneously, leading to a cyclic product with retained stereochemistry from the starting materials.
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- What two products are formed from each of the following reactions? b.
- a. The A ring of cortisone (a steroid) is formed by a Diels–Alder reaction using the two reactants shown here....
- b. The C ring of estrone (a steroid) is formed by a Diels–Alder reaction using the two reactants shown here. W...
- As many as 18 different Diels–Alder products can be obtained by heating a mixture of 1,3-butadiene and 2-methy...
- Identify the product of the following reaction.
- How would the following substituents affect the rate of a Diels–Alder reaction? c. an electron-withdrawing su...
- a. Which dienophile in each pair is more reactive in a Diels–Alder reaction? 1.
- a. Which dienophile in each pair is more reactive in a Diels–Alder reaction? 2.
- Predict the products of the following proposed Diels–Alder reactions. Include stereochemistry where appropriat...
- The highly reactive triple bond of benzyne is a powerful dienophile. Predict the product of the Diels–Alder re...
- (•) Provide a mechanism of the Diels–Alder reaction shown and predict the regioisomer that will form.
- (••) Predict the product of the Diels–Alder reactions shown. (a)
- (••••) While not covered explicitly in this chapter, the ene reaction occurs similarly to the Diels–Alder reac...
- Diene A participates in a fast and efficient Diels–Alder reaction with maleic anhydride, the powerful dienophi...
- Predict the product of the following Diels–Alder reactions. Where a racemic mixture is produced, show both ena...
- Figure 22.16(a) shows a unique example where the Diels–Alder reaction gives a single product (no enantiomers) ...
- Assuming the diene approaches the dienophile from the top, predict the product of the following Diels–Alder re...
- In each Diels–Alder reaction shown, predict the product that will result. (c)
- Show the steps involved in the following reaction:
- Predict the products of the following proposed Diels–Alder reactions. Include stereochemistry where appropriat...
- An important variation of the Diels–Alder reaction is intramolecular, in which the diene and the dienophile ar...
- Predict the products of the following proposed Diels–Alder reactions.(f) <IMAGE>
- In Solved Problem 15-2 we predicted that the products would have a 1,2- or 1,4-relationship of the proper subs...
- An important variation of the Diels–Alder reaction is intramolecular, in which the diene and the dienophile ar...
- An important variation of the Diels–Alder reaction is intramolecular, in which the diene and the dienophile ar...
- What is the major product when the X substituent in X reaction is bonded to X-2 of the diene rather than to X-...
- Explain why the following compounds are not optically active:a. the product obtained from the reaction of 1,3-...
- Explain why the following compounds are not optically active:b. the product obtained from the reaction of 1,3-...