Now I'm going to introduce the concepts and general features behind an analytical tool called infrared or IR spectroscopy. IR spec is a chemical analytical method that uses different frequencies of light to frequency of light to make chemical bonds stretch and bend. In general, we call these changes in the bonds vibrations. It causes the frequencies will cause the bonds to vibrate in different ways. Now there's actually a bunch of different types of vibrations that are possible: stretching, twisting, wagging, scissoring, rocking. That's another one. But for the purposes of this course, we're really going to treat them all the same and we're just going to refer to all of them as vibrations. Okay? Now the whole idea behind IR spec is that we can use different frequencies of light to make different types of bonds vibrate because different bonds will vibrate or resonate at different types of frequencies. And if we plot out the movements of the bonds with the wavelengths of the light that we're using, we can actually get a pretty good idea of what type of bonds are in the solution that we are testing. Okay. Now, there is one kind of exception to this analytical method, or maybe a limitation would be a better way to say it, which is that if a molecule is perfectly symmetrical, as an example, N2. N2 is a gas. Recall that it's a nitrogen, triple bond nitrogen, lone pair, lone pair. There's only one bond there and this molecule is perfectly symmetrical, so this would not result in my IR spectrum. Now this isn't something that we really have to worry about in real life because everything we're going to be analyzing in this course is going to be large asymmetrical molecules often with multiple functional groups. We don't really have to worry about this but it is something to know as a conceptual question. Now what I'd like to do is introduce kind of the general features of the IR spectrum and kind of explain what we're looking at here. Because when we put the molecule inside the IR machine, guess what we're going to get? We're going to get something crazy looking like this. A bunch of peaks, a bunch of troughs. It kind of looks like we're walking into a cave. Okay? And we've got all these stalactites that are about to fall on us. Alright? Well, these are not stalactites. What we actually call them is absorptions. Okay. So I'm just going to write that word here. Absorptions. Okay. And absorptions are one of the things that we plot in an IR spectrum because it basically tells us how much of the light is getting absorbed. So let's just talk about the x and the y axis here. Let's actually start off with the y axis. The y axis has to do with transmittance. Now I know you can't really see that word. I'm sorry. It's so small. Maybe you can see it on the paper that you printed. But it just basically says that either 100 percent of the light is getting transmitted or it's getting through the sample. That means that it didn't get absorbed or all the way down to 0% got through. If 0% got through, that means all of it got absorbed. This thing right here, this big, little, like, stalactite looking thing would be what we call an absorption. That's an area where that specific wavelength of light did not get through the sample. It actually got almost fully absorbed. Notice that it's all the way almost down to like 5%. Okay? That means 95% of this light, of this frequency did not make it through the entire sample. Cool so far? Now let's talk about the x axis. The x axis has to do with those different frequencies of light and it's measured in something we call wave number. I'm just going to write this out again. Wave number. Now you might think that wave number is the same thing as wavelength, but it's actually not. It's a weird way to measure frequency. It's measured in centimeters, the reciprocal of centimeters. But really what this is a measure of is more like frequency. All you need to know is that as your wave number increases, your frequency also increases of the light. We've got it starts off at 0 and it ends up around 4,000. Those are the different frequencies that we're measuring. Now you see you get this pretty graph. You kind of understand the axis a little better. Now how does this actually relate to chemistry, right? Well, basically different types of bonds. As you can see, I've already written out some basic functional groups here, some basic bonds. These are going to be the ones that can result in different places on the spectrum. The first and most important distinction we have to make about the spectrum is that it has 2 big regions. We're going to separate it as the region below 1500 and the region above 1500. The region below 1500 is what we call the fingerprint region. Now why do we call it that? Because this fingerprint region is going to have so much variation in it and so many different peaks and troughs coming out of it that almost the only information that we can get out of it is kind of like a fingerprint. Okay. So you could imagine that if you took my fingerprint, okay, what kind of information does that fingerprint give you? Does it tell you, that I am male? Does it tell you my ethnicity? Does it tell you, you know, that I like certain food? No. It really only tells you that I'm Johnny, right? It just identifies me as a person. And that's kind of the information that we get from the fingerprint region. All it really does is it helps to differentiate one molecule from another, but it doesn't tell us much about what the molecule actually is. Okay. It doesn't tell us if the molecule is an ether nor if the molecule well, it can sometimes but it's very difficult to to read and very kind of unreliable. For the purposes of this course, guess what we're going to do? We're going to ignore the fingerprint region. We're never going to discuss wave numbers below 1500. I just want to make a note to say that this is the part where professors can kind of vary and you may have be just lucky enough to have one of those professors that actually cares a little bit about the fingerprint region. I'm going to leave that up to you as homework to ask your professor, professor, is there anything I need to memorize about the fingerprint region? But for the purposes of clutch prep, we're going to focus on everything above 1500 because that's the part of the spectrum that's much more commonly tested. Now that I've said that, what's the part that matters? The functional group region. Now the functional group region is the region that actually we can get information about the types of bonds, the types of functional groups. It actually tells us what type of molecule we're looking at. Now you notice that I also have these kind of lines in between in different areas on the spectrum. These lines represent different themes or different types of bonds that I can see in the spectrum. The fingerprint region is going to be the region where we see single bonds. I'm going to write this here. Single bonds. And this is where bonds like Csingle bond C, Csingle bond N, Csingle bond O, Csingle bond X. Recall that's a halogen. Right? So single bonds are going to result in that region of the spectrum. Now that does make it challenging because you can think that a molecule is going to have lots and lots of these single bonds. So this spectrum, this part of spectrum is going to be a mess. It's going to be a collection of a bunch of different things coming from all those single bonds. We're really going to pretty much ignore all of those bonds and we're going to focus on the ones that are in the functional group. Well, what kind of bonds do we get in the functional group region? Well, we get for the range between 1500-2000, we get the double bond region. Now the idea behind the double bond region being a higher wave number than the single bond region is that these molecules are going to vibrate at higher frequency. And when you have a really, really tight spring and and when you have a really, really tight spring and you flip it really quick or you just put your finger on it, it's going to vibrate really, really fast. Okay? And when you have a loose spring that's not really that strong, it's going to vibrate a little bit more slowly. Okay. Well, double bonds are stronger than single bonds. I would imagine that it's going to vibrate at a faster frequency than a single bond would. And that's why it's going to result at a higher wave number. The types of bonds that we see in the double bond region are like Cdouble bond C, Cdouble bond O, Cdouble bond N, even like when you have 2 double bonds in a row that's called a cumulene. You could even see something like that. Pretty much anything in the double bond region is going to be between 1500-2100. That's because it's going to vibrate a little bit faster than the single bonds would have. Well, now that we talked about double bonds, what do you guys think comes next? What's the next stronger type of bond? You got it. So the next region between 2000 and about 2500, this line is actually a little bit further than I would have liked. I'm the spectrum. It's not drawn to scale. But from about 2000 to 2500, we have the triple bond region. Okay. And the triple bond region is going to vibrate even a little bit faster because it's stronger. And this is where we're going to see things like Ctriple bond C and Ctriple bond N. Those are the 2 most common types of bonds that result there. Okay? So now we've done single which we're going to ignore. Double and triple that are both in my functional group region. What do you think comes next? What's going to be the next type of bond that's going to vibrate even faster than triple bonds? I really hope you didn't say quadruple bonds because those are very rare and, they really wouldn't work with a lot of the molecules we're using. So it could be a mystery. I'll just tell you. It's actually going to be single bonds again. Wait. Wait for it. It's single bonds to hydrogen. The reason is that hydrogen is the smallest, lightest element. So even though the single bond is not that strong by itself, it also has a very tiny thing on the end. So if you can imagine that this spring is very, very light because it has this very little atom on it, it's still going to vibrate really fast even though it's not a very tight spring. Get it? So the hydrogen makes it actually vibrate faster than even a triple bond. So what kind of bonds do we see in the single bond to H region? Well, that's where we're going to have our CHgroup, ROHgroup, our NHgroup. I'm just going to dip into it a little bit. Pretty much those are the ones that we're going to deal with. Okay? We're going to see a lot of those. That kind of explains the general regions of the spectrum. It does get more complicated because we're actually going to have to memorize the absorptions of different types of bonds. But for right now, even if you forgot the exact absorption and even if all you knew was these regions, it already gives you kind of a reference point to know where would this thing tend to resolve. Now what I want to do is just go over quickly because we're going to do this in more depth. I want to quickly go over just some major absorptions and kind of show you where they would result here. As you can see, my double bond CC and my double bond CO both results around the same place. Now what we're going to notice is that later on when I talk about this, I'm going to go into more detail about Cdouble bond O especially. It's not always at 1700 but it's in the range. You could see this definitely puts it well within the double bond region. Okay? And what we're going to notice is that I have these words over here. What do these words represent? Well, I've got words like strong, medium, and then comma, sharp. What is that talking about? Well, it turns out that I know this is a lot to explain but scientists can never just use common words like normal stuff. They have to make up their own. Right? So the first word, the very strong or medium. Okay. So I'm just going to say that the first descriptive word is actually talking about the size of the peak or the size of the absorption. Basically, the first word has to do with what we could call length. Very strong would mean that it's a very long absorption and medium or small would mean that it's a very short absorption. Okay? So that's the first word. Then we have the second word. So I'm going to put a comma, second word. What does the second word represent? Okay. Well, that's going to be words like sharp or broad. As you can see, I've got here broad. So that word represents the width. With sharp meaning that it's very narrow. Think of it almost like a sharp stalactite. If it falls on you, it's going to cut right through you. And then broad, meaning that it's very wide, kind of like if it fell on you, it would just crush your entire body. It wouldn't split you in half. This is getting gruesome so I'll stop. Okay. But you can see that basically when we describe them, we're usually saying length and then width. As you can see, these ranges here I'm actually going to take myself out of the camera really quick. Oh. I just messed that one up. Sorry. Okay. I'm not taking myself out of the camera but I'm just going to step out of the way to show you that the absorptions are actually very similar for these guys but their shapes are different. That's what we're going to focus on in the double bond region that their shapes are very different. Now when we move on to the triple bond region, we see that triple bonds tend to result around the same place but safely between 2000-21500. And then we see that all of our bonds to H result in differing places depending on where they are, but they're all in the 3000 range or more. What I'm going to do is during the course of this lesson, I'm actually going to go over much more specifically what all of these different peaks look like. But for right now, I'm just trying to give you kind of a general framework so that later on when we discuss the exact shapes, you guys will be able to recall how it looks on the actual spectrum. With that said, let's go ahead and move on to the next part.
- 1. A Review of General Chemistry5h 5m
- Summary23m
- Intro to Organic Chemistry5m
- Atomic Structure16m
- Wave Function9m
- Molecular Orbitals17m
- Sigma and Pi Bonds9m
- Octet Rule12m
- Bonding Preferences12m
- Formal Charges6m
- Skeletal Structure14m
- Lewis Structure20m
- Condensed Structural Formula15m
- Degrees of Unsaturation15m
- Constitutional Isomers14m
- Resonance Structures46m
- Hybridization23m
- Molecular Geometry16m
- Electronegativity22m
- 2. Molecular Representations1h 14m
- 3. Acids and Bases2h 46m
- 4. Alkanes and Cycloalkanes4h 19m
- IUPAC Naming29m
- Alkyl Groups13m
- Naming Cycloalkanes10m
- Naming Bicyclic Compounds10m
- Naming Alkyl Halides7m
- Naming Alkenes3m
- Naming Alcohols8m
- Naming Amines15m
- Cis vs Trans21m
- Conformational Isomers13m
- Newman Projections14m
- Drawing Newman Projections16m
- Barrier To Rotation7m
- Ring Strain8m
- Axial vs Equatorial7m
- Cis vs Trans Conformations4m
- Equatorial Preference14m
- Chair Flip9m
- Calculating Energy Difference Between Chair Conformations17m
- A-Values17m
- Decalin7m
- 5. Chirality3h 39m
- Constitutional Isomers vs. Stereoisomers9m
- Chirality12m
- Test 1:Plane of Symmetry7m
- Test 2:Stereocenter Test17m
- R and S Configuration43m
- Enantiomers vs. Diastereomers13m
- Atropisomers9m
- Meso Compound12m
- Test 3:Disubstituted Cycloalkanes13m
- What is the Relationship Between Isomers?16m
- Fischer Projection10m
- R and S of Fischer Projections7m
- Optical Activity5m
- Enantiomeric Excess20m
- Calculations with Enantiomeric Percentages11m
- Non-Carbon Chiral Centers8m
- 6. Thermodynamics and Kinetics1h 22m
- 7. Substitution Reactions1h 48m
- 8. Elimination Reactions2h 30m
- 9. Alkenes and Alkynes2h 9m
- 10. Addition Reactions3h 18m
- Addition Reaction6m
- Markovnikov5m
- Hydrohalogenation6m
- Acid-Catalyzed Hydration17m
- Oxymercuration15m
- Hydroboration26m
- Hydrogenation6m
- Halogenation6m
- Halohydrin12m
- Carbene12m
- Epoxidation8m
- Epoxide Reactions9m
- Dihydroxylation8m
- Ozonolysis7m
- Ozonolysis Full Mechanism24m
- Oxidative Cleavage3m
- Alkyne Oxidative Cleavage6m
- Alkyne Hydrohalogenation3m
- Alkyne Halogenation2m
- Alkyne Hydration6m
- Alkyne Hydroboration2m
- 11. Radical Reactions1h 58m
- 12. Alcohols, Ethers, Epoxides and Thiols2h 42m
- Alcohol Nomenclature4m
- Naming Ethers6m
- Naming Epoxides18m
- Naming Thiols11m
- Alcohol Synthesis7m
- Leaving Group Conversions - Using HX11m
- Leaving Group Conversions - SOCl2 and PBr313m
- Leaving Group Conversions - Sulfonyl Chlorides7m
- Leaving Group Conversions Summary4m
- Williamson Ether Synthesis3m
- Making Ethers - Alkoxymercuration4m
- Making Ethers - Alcohol Condensation4m
- Making Ethers - Acid-Catalyzed Alkoxylation4m
- Making Ethers - Cumulative Practice10m
- Ether Cleavage8m
- Alcohol Protecting Groups3m
- t-Butyl Ether Protecting Groups5m
- Silyl Ether Protecting Groups10m
- Sharpless Epoxidation9m
- Thiol Reactions6m
- Sulfide Oxidation4m
- 13. Alcohols and Carbonyl Compounds2h 17m
- 14. Synthetic Techniques1h 26m
- 15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
- Purpose of Analytical Techniques5m
- Infrared Spectroscopy16m
- Infrared Spectroscopy Table31m
- IR Spect:Drawing Spectra40m
- IR Spect:Extra Practice26m
- NMR Spectroscopy10m
- 1H NMR:Number of Signals26m
- 1H NMR:Q-Test26m
- 1H NMR:E/Z Diastereoisomerism8m
- H NMR Table24m
- 1H NMR:Spin-Splitting (N + 1) Rule22m
- 1H NMR:Spin-Splitting Simple Tree Diagrams11m
- 1H NMR:Spin-Splitting Complex Tree Diagrams12m
- 1H NMR:Spin-Splitting Patterns8m
- NMR Integration18m
- NMR Practice14m
- Carbon NMR4m
- Structure Determination without Mass Spect47m
- Mass Spectrometry12m
- Mass Spect:Fragmentation28m
- Mass Spect:Isotopes27m
- 16. Conjugated Systems6h 13m
- Conjugation Chemistry13m
- Stability of Conjugated Intermediates4m
- Allylic Halogenation12m
- Reactions at the Allylic Position39m
- Conjugated Hydrohalogenation (1,2 vs 1,4 addition)26m
- Diels-Alder Reaction9m
- Diels-Alder Forming Bridged Products11m
- Diels-Alder Retrosynthesis8m
- Molecular Orbital Theory9m
- Drawing Atomic Orbitals6m
- Drawing Molecular Orbitals17m
- HOMO LUMO4m
- Orbital Diagram:3-atoms- Allylic Ions13m
- Orbital Diagram:4-atoms- 1,3-butadiene11m
- Orbital Diagram:5-atoms- Allylic Ions10m
- Orbital Diagram:6-atoms- 1,3,5-hexatriene13m
- Orbital Diagram:Excited States4m
- Pericyclic Reaction10m
- Thermal Cycloaddition Reactions26m
- Photochemical Cycloaddition Reactions26m
- Thermal Electrocyclic Reactions14m
- Photochemical Electrocyclic Reactions10m
- Cumulative Electrocyclic Problems25m
- Sigmatropic Rearrangement17m
- Cope Rearrangement9m
- Claisen Rearrangement15m
- 17. Ultraviolet Spectroscopy51m
- 18. Aromaticity2h 34m
- 19. Reactions of Aromatics: EAS and Beyond5h 1m
- Electrophilic Aromatic Substitution9m
- Benzene Reactions11m
- EAS:Halogenation Mechanism6m
- EAS:Nitration Mechanism9m
- EAS:Friedel-Crafts Alkylation Mechanism6m
- EAS:Friedel-Crafts Acylation Mechanism5m
- EAS:Any Carbocation Mechanism7m
- Electron Withdrawing Groups22m
- EAS:Ortho vs. Para Positions4m
- Acylation of Aniline9m
- Limitations of Friedel-Crafts Alkyation19m
- Advantages of Friedel-Crafts Acylation6m
- Blocking Groups - Sulfonic Acid12m
- EAS:Synergistic and Competitive Groups13m
- Side-Chain Halogenation6m
- Side-Chain Oxidation4m
- Reactions at Benzylic Positions31m
- Birch Reduction10m
- EAS:Sequence Groups4m
- EAS:Retrosynthesis29m
- Diazo Replacement Reactions6m
- Diazo Sequence Groups5m
- Diazo Retrosynthesis13m
- Nucleophilic Aromatic Substitution28m
- Benzyne16m
- 20. Phenols55m
- 21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
- Naming Aldehydes8m
- Naming Ketones7m
- Oxidizing and Reducing Agents9m
- Oxidation of Alcohols28m
- Ozonolysis7m
- DIBAL5m
- Alkyne Hydration9m
- Nucleophilic Addition8m
- Cyanohydrin11m
- Organometallics on Ketones19m
- Overview of Nucleophilic Addition of Solvents13m
- Hydrates6m
- Hemiacetal9m
- Acetal12m
- Acetal Protecting Group16m
- Thioacetal6m
- Imine vs Enamine15m
- Addition of Amine Derivatives5m
- Wolff Kishner Reduction7m
- Baeyer-Villiger Oxidation39m
- Acid Chloride to Ketone7m
- Nitrile to Ketone9m
- Wittig Reaction18m
- Ketone and Aldehyde Synthesis Reactions14m
- 22. Carboxylic Acid Derivatives: NAS2h 51m
- Carboxylic Acid Derivatives7m
- Naming Carboxylic Acids9m
- Diacid Nomenclature6m
- Naming Esters5m
- Naming Nitriles3m
- Acid Chloride Nomenclature5m
- Naming Anhydrides7m
- Naming Amides5m
- Nucleophilic Acyl Substitution18m
- Carboxylic Acid to Acid Chloride6m
- Fischer Esterification5m
- Acid-Catalyzed Ester Hydrolysis4m
- Saponification3m
- Transesterification5m
- Lactones, Lactams and Cyclization Reactions10m
- Carboxylation5m
- Decarboxylation Mechanism14m
- Review of Nitriles46m
- 23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
- 24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
- Tautomerization9m
- Tautomers of Dicarbonyl Compounds6m
- Enolate4m
- Acid-Catalyzed Alpha-Halogentation4m
- Base-Catalyzed Alpha-Halogentation3m
- Haloform Reaction8m
- Hell-Volhard-Zelinski Reaction3m
- Overview of Alpha-Alkylations and Acylations5m
- Enolate Alkylation and Acylation12m
- Enamine Alkylation and Acylation16m
- Beta-Dicarbonyl Synthesis Pathway7m
- Acetoacetic Ester Synthesis13m
- Malonic Ester Synthesis15m
- 25. Condensation Chemistry2h 9m
- 26. Amines1h 43m
- 27. Heterocycles2h 0m
- Nomenclature of Heterocycles15m
- Acid-Base Properties of Nitrogen Heterocycles10m
- Reactions of Pyrrole, Furan, and Thiophene13m
- Directing Effects in Substituted Pyrroles, Furans, and Thiophenes16m
- Addition Reactions of Furan8m
- EAS Reactions of Pyridine17m
- SNAr Reactions of Pyridine18m
- Side-Chain Reactions of Substituted Pyridines20m
- 28. Carbohydrates5h 53m
- Monosaccharide20m
- Monosaccharides - D and L Isomerism9m
- Monosaccharides - Drawing Fischer Projections18m
- Monosaccharides - Common Structures6m
- Monosaccharides - Forming Cyclic Hemiacetals12m
- Monosaccharides - Cyclization18m
- Monosaccharides - Haworth Projections13m
- Mutarotation11m
- Epimerization9m
- Monosaccharides - Aldose-Ketose Rearrangement8m
- Monosaccharides - Alkylation10m
- Monosaccharides - Acylation7m
- Glycoside6m
- Monosaccharides - N-Glycosides18m
- Monosaccharides - Reduction (Alditols)12m
- Monosaccharides - Weak Oxidation (Aldonic Acid)7m
- Reducing Sugars23m
- Monosaccharides - Strong Oxidation (Aldaric Acid)11m
- Monosaccharides - Oxidative Cleavage27m
- Monosaccharides - Osazones10m
- Monosaccharides - Kiliani-Fischer23m
- Monosaccharides - Wohl Degradation12m
- Monosaccharides - Ruff Degradation12m
- Disaccharide30m
- Polysaccharide11m
- 29. Amino Acids3h 20m
- Proteins and Amino Acids19m
- L and D Amino Acids14m
- Polar Amino Acids14m
- Amino Acid Chart18m
- Acid-Base Properties of Amino Acids33m
- Isoelectric Point14m
- Amino Acid Synthesis: HVZ Method12m
- Synthesis of Amino Acids: Acetamidomalonic Ester Synthesis16m
- Synthesis of Amino Acids: N-Phthalimidomalonic Ester Synthesis13m
- Synthesis of Amino Acids: Strecker Synthesis13m
- Reactions of Amino Acids: Esterification7m
- Reactions of Amino Acids: Acylation3m
- Reactions of Amino Acids: Hydrogenolysis6m
- Reactions of Amino Acids: Ninhydrin Test11m
- 30. Peptides and Proteins2h 42m
- Peptides12m
- Primary Protein Structure4m
- Secondary Protein Structure17m
- Tertiary Protein Structure11m
- Disulfide Bonds17m
- Quaternary Protein Structure10m
- Summary of Protein Structure7m
- Intro to Peptide Sequencing2m
- Peptide Sequencing: Partial Hydrolysis25m
- Peptide Sequencing: Partial Hydrolysis with Cyanogen Bromide7m
- Peptide Sequencing: Edman Degradation28m
- Merrifield Solid-Phase Peptide Synthesis18m
- 32. Lipids 2h 50m
- 34. Nucleic Acids1h 32m
- 35. Transition Metals5h 33m
- Electron Configuration of Elements45m
- Coordination Complexes20m
- Ligands24m
- Electron Counting10m
- The 18 and 16 Electron Rule13m
- Cross-Coupling General Reactions40m
- Heck Reaction40m
- Stille Reaction13m
- Suzuki Reaction25m
- Sonogashira Coupling Reaction17m
- Fukuyama Coupling Reaction15m
- Kumada Coupling Reaction13m
- Negishi Coupling Reaction16m
- Buchwald-Hartwig Amination Reaction19m
- Eglinton Reaction17m
- 36. Synthetic Polymers1h 49m
- Introduction to Polymers6m
- Chain-Growth Polymers10m
- Radical Polymerization15m
- Cationic Polymerization8m
- Anionic Polymerization8m
- Polymer Stereochemistry3m
- Ziegler-Natta Polymerization4m
- Copolymers6m
- Step-Growth Polymers11m
- Step-Growth Polymers: Urethane6m
- Step-Growth Polymers: Polyurethane Mechanism10m
- Step-Growth Polymers: Epoxy Resin8m
- Polymers Structure and Properties8m
Infrared Spectroscopy - Online Tutor, Practice Problems & Exam Prep
Infrared (IR) spectroscopy is a chemical analytical method that measures bond vibrations in molecules using different light frequencies. The IR spectrum is divided into two main regions: the fingerprint region (below 1500 cm-1), which identifies molecules, and the functional group region (above 1500 cm-1), which reveals specific bond types. Key bond types include single, double, and triple bonds, with their vibrational frequencies increasing with bond strength. Understanding these regions and their corresponding absorptions is crucial for identifying molecular structures in organic chemistry.
General Features of IR Spect
Video transcript
Do you want more practice?
More setsHere’s what students ask on this topic:
What is infrared (IR) spectroscopy and how does it work?
Infrared (IR) spectroscopy is an analytical technique used to identify and study chemicals by measuring the vibrations of bonds within molecules. When a molecule is exposed to infrared light, different frequencies of light cause the chemical bonds to stretch, bend, and vibrate in various ways. These vibrations are specific to the types of bonds and functional groups present in the molecule. The IR spectrum is plotted with transmittance on the y-axis and wave number (cm-1) on the x-axis. Peaks in the spectrum, known as absorptions, indicate the frequencies at which the light is absorbed, providing information about the molecular structure.
What are the main regions of an IR spectrum and what do they represent?
The IR spectrum is divided into two main regions: the fingerprint region (below 1500 cm-1) and the functional group region (above 1500 cm-1). The fingerprint region is highly complex and unique to each molecule, making it useful for identifying specific compounds but not for determining functional groups. The functional group region provides information about specific bond types and functional groups. It includes the single bond region (1500-2000 cm-1), double bond region (2000-2500 cm-1), triple bond region (2500-3000 cm-1), and the region for single bonds to hydrogen (above 3000 cm-1).
How do you interpret the peaks in an IR spectrum?
Interpreting peaks in an IR spectrum involves analyzing their position, size, and shape. The position (wave number) indicates the type of bond or functional group. For example, C=O bonds typically appear around 1700 cm-1. The size (intensity) of the peak, described as strong, medium, or weak, indicates how much light is absorbed. The shape, described as sharp or broad, provides additional information about the bond environment. For instance, O-H stretches are usually broad due to hydrogen bonding. By comparing these characteristics to known values, you can identify the functional groups present in the molecule.
What is the fingerprint region in IR spectroscopy and why is it important?
The fingerprint region in IR spectroscopy is the part of the spectrum below 1500 cm-1. It is called the fingerprint region because it contains a complex pattern of peaks unique to each molecule, much like a human fingerprint. This region is important for identifying specific compounds, as the pattern of absorptions can be used to distinguish one molecule from another. However, it is less useful for identifying functional groups due to its complexity. In many cases, the fingerprint region is used in conjunction with the functional group region to confirm the identity of a molecule.
What are the limitations of IR spectroscopy?
IR spectroscopy has several limitations. One major limitation is that it cannot detect symmetrical molecules, such as N2 or O2, because they do not have a dipole moment and thus do not absorb IR light. Additionally, the fingerprint region can be very complex and difficult to interpret, making it challenging to identify specific functional groups. IR spectroscopy also requires relatively pure samples, as impurities can interfere with the spectrum. Finally, it provides limited information about the overall structure of large, complex molecules, often requiring complementary techniques for a complete analysis.
Your Organic Chemistry tutors
- A C-D (carbon–deuterium) bond is electronically much like a C-H bond, and it has a similar stiffness, measure...
- Which of the bonds shown in red are expected to have IR-active stretching frequencies? (a) (b) (c) (d) (e...
- Convert the following infrared wavelengths to cm-1. (a) 6.24 𝜇m, typical for an aromatic C=C (b) 3.38 𝜇m, t...
- Which of the following compounds has a vibration that is infrared inactive? 1-butyne, 2-butyne, H2
- Assuming that the force constant is approximately the same for C-C, C-N, and C-O bonds, predict the relative p...
- Why is the C-O absorption band of 1-hexanol at a smaller wavenumber (1060 cm-1) than the C-O absorption band o...
- Which occurs at a larger wavenumber: a. the C-O stretch of phenol or the C-O stretch of cyclohexanol? b. the C...
- a. Which occurs at a larger wavenumber: 3. a C-N stretch or a C=N stretch? 4. a C=O stretch or a C-O stretch...
- Rank the following compounds from highest wavenumber to lowest wavenumber for their C=O absorption bands: b.
- Calculate the reduced mass for the following bonds. (a) C―H
- Calculate the reduced mass for the following bonds. (c) C―Cl
- Would you expect an acetylenic C―H to absorb at a higher or lower wavenumber than the C―H in ethene?
- For each pair, choose the molecule that you expect to have the highest wavenumber for its C=O stretch. (d)
- (••) Based on Hooke's law, choose the bond in each pair that you expect to vibrate at a higher wavenumber. (e...
- (••) Based on Hooke's law, choose the bond in each pair that you expect to vibrate at a higher wavenumber. (f...
- (••) Choose the bond in each pair that you expect to have the more intense stretching band (b) C=O vs. C=N
- LOOKING AHEAD We explain in Chapter 23 that substituents can transmit electronic information through the benze...
- LOOKING AHEAD We explain in Chapter 23 that substituents can transmit electronic information through the benze...
- LOOKING AHEAD We explain in Chapter 23 that substituents can transmit electronic information through the benze...
- Choose the bond in each pair that you expect to vibrate at the higher wavenumber. (a) C―N vs. C = N
- Choose the bond in each pair that you expect to vibrate at the higher wavenumber. (b) C―H vs. C―O
- LOOKING AHEAD We explain in Chapter 23 that substituents can transmit electronic information through the benze...
- LOOKING AHEAD We explain in Chapter 23 that substituents can transmit electronic information through the benze...
- There are three carbon–oxygen bonds in methyl acetate. a. What are their relative bond lengths? b. What are ...