So the first hemp protecting group that you need to know and probably one of the more common ones is a tert-butyl ether protecting group. Now what this does is it adds an ether to the oxygen making it unreactive. Because if you guys remember or if you guys have just learned about functional groups in the past, alcohols participate in a lot more reactions than ethers do. So what that means is that if I can turn my alcohol into an ether, it's going to be protected as long as it is an ether. Now the reaction that we usually use for this is an acid catalyzed alkoxylation. Just so you know, an acid catalyzed alkoxylation is a lot like an acid catalyzed hydration except that we're using an alcohol as our solvent. In this case, the alcohol actually comes from my molecule. So let's go ahead and draw out this mechanism. We're going to react with a molecule called isobutylene, which is just this 4 membered hydrocarbon with a double bond. And what we're going to wind up getting is an ether. Let's figure out how. In our first step, we're going to protonate our double bond through a normal addition mechanism. What this is going to give me is a Markovnikov carbocation. Remember that Markovnikov states that your carbocation goes in the more stable position. After I've done that, given the electrons to the O, what happens next? Well, now it's time for my alcohol to step in. So my alcohol is actually going to wind up attacking that carbocation. What I'm going to make is something that looks like this, where now I have a tert-butyl group on one side, the ring structure on the other. I still have one H and a positive charge. Now how do you think we could get rid of that positive charge? Smart. What we could do is we could use the conjugate of my original acid. So I'm going to go ahead and use the conjugate of my sulfuric acid. I'm going to deprotonate and lo and behold, look what I've got. I now have an ether instead of an alcohol. Now why do you think this might be helpful? Having it look like that. Well, because it turns out that this ether that I'm looking at right here is completely unreactive to strong bases like alkynides. Remember that I said an alkynide would react with an alcohol? It won't react with an ether. So now that means if I were to introduce my alkynide to this molecule after the ether is in place, guess where it's going to react. Not with the ether. The ether is protected now. This is my protecting group. Okay. That's my protecting group. Okay? So now what's going to happen is that the only thing that it can possibly react with is my alkyl halide through an SN 2 reaction. So that's the advantage of protecting groups. They allow us to react with just the thing we want and to ignore the thing that we don't want to react with. Now you might be wondering, Johnny, what does the final product look like? Well, what we would do at this point is that we could, after this reaction is over, remove the protecting group. Why is that? Because we said this reaction has to be easily reversible, right? So what that means is that see how this is drawn with a positive arrow, I mean with a forward-looking arrow? Well, actually, it would be truly in equilibrium. It wouldn't be just a forwards arrow. So for example, here I drew a forwards arrow here. That should really be technically it should be in equilibrium, right? Because we know that it's going to go forwards now, but we can make it go backwards later. After we do this step, how do we get it back to the original alcohol? Well, if adding our protecting group was step 1 and if adding our alkynide was step 2, then we have a third step. And the third step is just to add mild acid. So I could just say HQSO4 and water. And what that's going to do is that's going to deprotect. Whenever you protect, you always have to deprotect. What does deprotect mean? It just means that I'm going to take that ether completely off. Now I'm not going to show you the whole mechanism to deprotect, but you can imagine it's just the reverse mechanism of everything we've drawn to protect it. What that means is that I would actually protonate the O first, then it would leave and then it would get protonated. The tert-butyl group would leave and then it would get protonated. All right. And eliminate it. All right. So I hope that makes sense guys. For the purposes of your test, you will need to know when you have to use a protecting group and when you don't. Okay? In terms of synthesis, your professor could ask you, hey, how do I make this final product? Just using that one reagent wouldn't be enough. You would need to use first, you need to protect. Second, you could use your alkynide. And then third, you would have to deprotect using acid and water. Okay? So I hope that made sense guys. Let me know if you have any questions. If not, let's go ahead and move to the next topic.
- 1. A Review of General Chemistry5h 5m
- Summary23m
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- Atomic Structure16m
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- What is the Relationship Between Isomers?16m
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- Addition Reaction6m
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- 11. Radical Reactions1h 58m
- 12. Alcohols, Ethers, Epoxides and Thiols2h 42m
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- Williamson Ether Synthesis3m
- Making Ethers - Alkoxymercuration4m
- Making Ethers - Alcohol Condensation4m
- Making Ethers - Acid-Catalyzed Alkoxylation4m
- Making Ethers - Cumulative Practice10m
- Ether Cleavage8m
- Alcohol Protecting Groups3m
- t-Butyl Ether Protecting Groups5m
- Silyl Ether Protecting Groups10m
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- Thiol Reactions6m
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- Blocking Groups - Sulfonic Acid12m
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- Overview of Alpha-Alkylations and Acylations5m
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- 25. Condensation Chemistry2h 9m
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- Nomenclature of Heterocycles15m
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- 29. Amino Acids3h 20m
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- Acid-Base Properties of Amino Acids33m
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- Reactions of Amino Acids: Esterification7m
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- 30. Peptides and Proteins2h 42m
- Peptides12m
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- Intro to Peptide Sequencing2m
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- 32. Lipids 2h 50m
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- Electron Configuration of Elements45m
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- Sonogashira Coupling Reaction17m
- Fukuyama Coupling Reaction15m
- Kumada Coupling Reaction13m
- Negishi Coupling Reaction16m
- Buchwald-Hartwig Amination Reaction19m
- Eglinton Reaction17m
t-Butyl Ether Protecting Groups - Online Tutor, Practice Problems & Exam Prep
The tert-butyl ether protecting group is crucial in organic synthesis, as it transforms reactive alcohols into unreactive ethers, preventing unwanted reactions. The process involves acid-catalyzed alkoxylation, where isobutylene reacts with an alcohol to form the ether. This protecting group allows selective reactions with alkyl halides via SN2 mechanisms. After the desired reactions, mild acid can deprotect the ether, restoring the original alcohol. Understanding when to use protecting groups is essential for successful synthesis and manipulation of functional groups in organic chemistry.
One way to protect alcohol is to form a reversible adduct with isobutylene via acid-catalyzed alkoxylation, yielding a temporary tert-butyl ether, which is completely unreactive.
Mechanism of t-Butyl Ether Protecting Groups.
Video transcript
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More setsHere’s what students ask on this topic:
What is a tert-butyl ether protecting group and why is it used in organic synthesis?
A tert-butyl ether protecting group is used in organic synthesis to transform reactive alcohols into unreactive ethers. This is crucial because alcohols can participate in many reactions, while ethers are much less reactive. By converting an alcohol to a tert-butyl ether, chemists can prevent unwanted side reactions, allowing selective reactions to occur. This is particularly useful in multi-step syntheses where specific functional groups need to be protected temporarily. The process involves an acid-catalyzed alkoxylation reaction with isobutylene, forming the ether. After the desired reactions, the protecting group can be removed using mild acid, restoring the original alcohol.
How is a tert-butyl ether protecting group added to an alcohol?
To add a tert-butyl ether protecting group to an alcohol, an acid-catalyzed alkoxylation reaction is used. The alcohol reacts with isobutylene in the presence of an acid catalyst, such as sulfuric acid. The mechanism involves protonation of the double bond in isobutylene, forming a carbocation. The alcohol then attacks this carbocation, resulting in the formation of a tert-butyl ether. This process effectively converts the alcohol into an unreactive ether, protecting it from further reactions.
What is the mechanism for removing a tert-butyl ether protecting group?
Removing a tert-butyl ether protecting group involves an acid-catalyzed deprotection process. Mild acid, such as dilute sulfuric acid in water, is used to protonate the ether oxygen. This protonation makes the ether more susceptible to cleavage, leading to the formation of a carbocation and the release of the original alcohol. The overall process is essentially the reverse of the protection mechanism, restoring the alcohol to its original form.
Why is it important to use protecting groups in organic synthesis?
Protecting groups are important in organic synthesis because they allow chemists to temporarily deactivate reactive functional groups. This selective deactivation prevents unwanted side reactions and enables specific reactions to occur at other sites in the molecule. For example, converting an alcohol to a tert-butyl ether protects it from reacting with strong bases or nucleophiles. After the desired reactions are completed, the protecting group can be removed, restoring the original functional group. This strategy is essential for the successful synthesis and manipulation of complex molecules.
What are the advantages of using tert-butyl ether as a protecting group?
The advantages of using tert-butyl ether as a protecting group include its stability and ease of removal. Tert-butyl ethers are unreactive to many reagents, such as strong bases and nucleophiles, making them excellent for protecting alcohols during multi-step syntheses. Additionally, the protecting group can be easily removed under mild acidic conditions, restoring the original alcohol without damaging other functional groups. This combination of stability and reversibility makes tert-butyl ether a valuable tool in organic synthesis.