Boron tribromide (BBr3) cleaves ethers to give alkyl halides
and alcohols.
R-O-R′ + BBr3 → R-O-BBr2 + R′Br
R-O-BBr2 + 3H2O → ROH + B(OH)3 + 2HBr
The reaction is thought to involve attack by a bromide ion
on the Lewis acid–base adduct of the ether with BBr3
(a strong Lewis acid).
Propose a mechanism for the reaction of butyl methyl ether
with BBr3 to give (after hydrolysis) butan-1-ol
and bromomethane.