The following compound seems like an unlikely candidate for exhibiting optical activity as all its atoms are sp² hybridized and should theoretically lie flat. However, the compound does display chirality and has been found to have an extremely high optical activity. Explain why the compound is optically active and has a high degree of specific rotation.

• A. The compound is nonplanar and adopts a twisted structure making it exist as enantiomers. On the other hand, electrons in the twisted π system interact with the plane-polarized light causing a high degree of specific rotation.
• B. The compound is nonaromatic and has a nonplanar structure making it exist as enantiomers. On the other hand, electrons in the π bonds interact with the plane-polarized light causing a high degree of specific rotation.
• C. The compound adopts a twisted structure making it exist as enantiomers. On the other hand, the lone pairs of nitrogen interact with the plane-polarized light causing a high degree of specific rotation.
• D. The compound is nonaromatic and has a nonplanar structure making it exist as enantiomers. On the other hand, the lone pairs of nitrogen interact with the plane-polarized light causing a high degree of specific rotation.