which-bonds-in-propoxybenzene-produce-the-two-c-o-stretching-bands-visible-in-it

Question

Which of the two C―O bonds in propoxybenzene produces a C―O stretching band at a higher wavenumber, and which produces a band at a lower wavenumber? What characteristic causes these bands to be intense?

Infrared spectrum graph showing transmittance vs. wavenumbers for propoxybenzene.

Chemical structure of propoxybenzene, showing the aromatic ring and ether group.

Accepted Answer

The C(sp²)―O bond produces a C―O stretching band at a higher wavenumber, while the C(sp³)―O bond produces the band at a lower wavenumber. The polarity of the C―O bond causes these bands to be intense.

Answer

The C(sp²)―O bond produces a C―O stretching band at a higher wavenumber, while the C(sp)―O bond produces the band at a lower wavenumber. The strength of the C―O bond causes these bands to be intense.

Answer

The C(sp)―O bond produces a C―O stretching band at a higher wavenumber, while the C(sp³)―O bond produces the band at a lower wavenumber. The length of the C―O bond causes these bands to be intense.

Answer

The C(sp³)―O bond produces a C―O stretching band at a higher wavenumber, while the C(sp²)―O bond produces the band at a lower wavenumber. The strength of the C―O bond causes these bands to be intense.

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Which of the two C―O bonds in propoxybenzene produces a C―O stretching band at a higher wavenumber, and which produces a band at a lower wavenumber? What characteristic causes these bands to be intense?