an-nmr-spectrum-of-an-unknown-compound-obtained-from-a-400-mhz-nmr-spectrometer-

Question

An NMR spectrum of an unknown compound obtained from a 400-MHz NMR spectrometer shows protons at a position 840 Hz downfield from the TMS.
(a) Determine the chemical shift of these protons.
(b) Determine their chemical shift in an 80-MHz NMR spectrometer.
(c) By how many Hz their chemical shift should be downfield from TMS using an 80-MHz NMR instrument?

Accepted Answer

(a). Chemical shift = 2.1 ppm
(b). Chemical shift = 2.1 ppm, the chemical shift of a given proton is the same regardless of the operating field and frequency of the spectrometer.
168 Hz downfield from TMS

Answer

(a). Chemical shift = 21 ppm
(b). Chemical shift = 21 ppm, the chemical shift of a given proton is the same regardless of the operating field and frequency of the spectrometer.
186 Hz downfield from TMS

Answer

(a). Chemical shift = 2.1 ppm
(b). Chemical shift = 4.2 ppm.
680 Hz downfield from TMS

Answer

(a). Chemical shift = 21 ppm
(b). Chemical shift = 0.8 ppm.
80 Hz downfield from TMS

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