consider-the-following-reverse-reaction-ch-ch3-2-hf-ch3-2ch2-f-the-activation-en

Question

Consider the following reaction:

•CH(CH₃)₂ + HF → (CH₃)₂CH₂ + F•

The activation energy and the heat of reaction (ΔH°) of its reverse reaction are 26.1 kJ/mol (6.24 kcal/mol) and −157 kJ/mol (−37.5 kcal/mol), respectively. Determine the activation energy and the heat of reaction (ΔH°) for the forward reaction.

Accepted Answer

E_{a, reverse} = 183 kJ/mol (43.7 kcal/mol)

ΔH°_reverse = 157 kJ/mol (37.5 kcal/mol)

Answer

E_{a, reverse} = −26.1 kJ/mol (−6.24 kcal/mol)

ΔH°_reverse = 157 kJ/mol (37.5 kcal/mol)

Answer

E_{a, reverse} = −26.1 kJ/mol (−6.24 kcal/mol)

ΔH°_reverse = −157 kJ/mol (−37.5 kcal/mol)

Answer

E_{a, reverse} = −183 kJ/mol (−43.7 kcal/mol)

ΔH°_reverse = 157 kJ/mol (37.5 kcal/mol)

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