for-the-acid-base-reactions-below-prove-that-the-equilibrium-lies-in-the-directi

Question

For the acid-base reactions below, prove that the equilibrium lies in the direction indicated in the reactions by comparing the pK_a values of the acids on both sides of the equilibrium arrow.

Accepted Answer

a. The pK_a values of the acids on both sides of the reaction are similar, so each would have a similar amount at equilibrium.

b. The pK_a value of the acid on the reactant side is greater, making it the weaker acid, so the reactant side is favored.

Answer

a. The pK_a values of the acids on both sides of the reaction are similar, so each would have a similar amount at equilibrium.

b. The pK_a value of the acid on the reactant side is greater, making it the stronger acid, so the reactant side is favored.

Answer

a. The pK_a value of the acid on the reactant side is greater, making it the stronger acid, so the reactant side is favored.

b. The pK_a value of the acid on the product side is greater, making it the stronger acid, so the product side is favored.

Answer

a. The pK_a value of the acid on the product side is lesser, making it the weaker acid, so the product side is favored.

b. The pK_a value of the acid on the product side is lesser, making it the weaker acid, so the product side is favored.

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