Refer to the information given in the table below. Provide the heat of hydrogenation (∆H°_hydr) for each step involved in the reduction of allylbenzene. 

∆H°_hydr (Step 1) + ∆H°_hydr (Step 2) + ∆H°_hydr (Step 3) + ∆H°_hydr (Step 4) = ∆H°_tot = –78.2 kcal/mol (–328 kJ/mol)

• A. Step 1: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)Step 2: ∆H°_hydr = –26.4 kcal/mol (111 kJ/mol)Step 3: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)Step 4: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)
• B. Step 1: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)Step 2: ∆H°_hydr = 5.4 kcal/mol (23 kJ/mol)Step 3: ∆H°_hydr = –26.4 kcal/mol (111 kJ/mol)Step 4: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)
• C. Step 1: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)Step 2: ∆H°_hydr = 7.6 kcal/mol (32 kJ/mol)Step 3: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)Step 4: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)
• D. Step 1: ∆H°_hydr = –28.6 kcal/mol (120 kJ/mol)Step 2: ∆H°_hydr = –26.4 kcal/mol (111 kJ/mol)Step 3: ∆H°_hydr = –26.4 kcal/mol (111 kJ/mol)Step 4: ∆H°_hydr = 3.2 kcal/mol (14 kJ/mol)

Answer: (B)