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1H NMR:Spin-Splitting (N + 1) Rule

1H NMR:Spin-Splitting (N + 1) Rule

15. Analytical Techniques:IR, NMR, Mass Spect / 1H NMR:Spin-Splitting (N + 1) Rule / Problem 4

Explain why the cis and trans isomers of the given alkene show no coupling between the a and c, as well as between the b and c protons.

ANSWERS OPTIONS

A

There is no coupling between a and c and between b and c protons because they are both too near to each other.

B

There is no coupling between a and c and between b and c protons because they are 6 and 4 pi bonds away from each other, respectively.

C

There is no coupling between a and c and between b and c protons because they are 4 and 6 sigma bonds away from each other, respectively.

D

There is no coupling between a and c and between b and c protons because they are 4 and 6 pi bonds away from each other, respectively.

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