Organic Chemistry
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Assuming the T = 298 K, determine the ∆G°, ∆H°, and ∆S° for the following reaction. Base the value of enthalpy (∆H°) on the structure of the conjugate bases.
∆G° = 2.02 kcal/mol
∆H° = 2.02 kcal/mol
∆S° = 0 kcal/mol
∆G° = 9.09 kcal/mol
∆H° = 9.09 kcal/mol
∆G° = −5.18 kcal/mol
∆H° = −5.18 kcal/mol
∆G° = −7.09 kcal/mol
∆H° = −7.09 kcal/mol
∆S° = 0