Organic Chemistry
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Refer to the information given in the table below. Provide the ∆H°hydr for each step involved in the reduction of allylbenzene.
∆H1 + ∆H2 + ∆H3 + ∆H4 = ∆Htot = –78.2 kcal/mol (–328 kJ/mol)
∆H1 = –28.6 kcal/mol (120 kJ/mol)
∆H2 = –26.4 kcal/mol (111 kJ/mol)
∆H3 = –28.6 kcal/mol (120 kJ/mol)
∆H4 = –28.6 kcal/mol (120 kJ/mol)
∆H2 = 5.4 kcal/mol (23 kJ/mol)
∆H3 = –26.4 kcal/mol (111 kJ/mol)
∆H2 = 7.6 kcal/mol (32 kJ/mol)
∆H4 = 3.2 kcal/mol (14 kJ/mol)