We know we need to start with the initiation step here. But even before we get to that, I want to ask you guys which hydrogen did you react the radical with, enoyalkane? Basically, there's actually only one choice that made sense, and you should have reacted it with the H right here. The reason is that this H belongs to the only tertiary carbon on this molecule. Now notice that there are no allylic sites here, so I don't worry about the resonance thing. I just worry about which hopefully this will be a learning experience for you. So now let's go ahead and draw the 3 steps. My first step is going to be initiation. I'll just draw it up here to make more room. Okay. So my initiation step is really easy. We're using XX again, so I'm just going to draw like that and like that. I'm going to do this. And what I'm going to wind up getting is 2 X radicals. Cool?
So now let's go into propagation. Now this is the part where it actually matters which hydrogen I used. And I just showed you guys why we're going to use that hydrogen there. I'm going to redraw my alkane and I'm going to draw the hydrogen sticking off this way this time just to make it easier to pull it off. I'm going to react that with x radical. And what that winds up giving me is 3 arrows. 1 here, 1 here, and 1 there. Okay? So what I wind up getting is a radical that looks like this. Okay? That radical plus HX. Okay? Now, what can that radical react with? Well, it in order to fully propagate and reproduce itself, it's going to have to react with another XX. So I'm going to do this, that, and that. And what that's going to give me is it's going to give me an alkyl halide. Notice that this is now a tertiary alkyl halide because I reacted it at a tertiary position, and I'm going to get that final radical. Cool. So now we're just going to end off with the termination step. And with the termination step, we basically had 3 different possibilities. We had X terminating with X. That would be my first product, and that would give me basically that would give me XX. Then we had another possibility, which was now my alkane radical terminating with a halogen radical. And what that would give me is another equivalent of a tertiary alkyl halide. And then, lastly, I had the third possibility, which would be I have basically 2 R groups colliding with each other. Okay? And that would give me a small amount of this kind of random-looking thing, which is going to be, that and then a single bond. And that single bond is attached to basically 2 more methyls and something like that. Okay? So anyway, I know that's ugly. Okay? But the whole point is that I can change the one. In the end of the day, I'm not going to get a whole lot of 1, I'm not going to get a whole lot of 3, but I am going to get a lot of 2. So my final product would be this guy. And then plus, I would get, obviously, a lot of HX as a byproduct. Okay? Because that's going to pretty much be forming all the time. Alright?