So here the example states, "What is the electron count of the neutral transition metal complex of Br₂Pd(CO)₂?" Alright. So first we have palladium as our transition metal. We have to give its electron configuration to determine the number of valence electrons it possesses. So remember, palladium has a unique electron configuration. It's just Krypton 4d¹⁰. It has no s orbital electrons. Those are promoted in order to completely fill up our d orbitals. So we have 10 d orbital electrons. So the valence electron count for palladium is 10 minus the charge of our complex. Here it has no charge; we're told it's neutral, so it's 0. Plus the number of X ligands, which in this case would be the 2 bromines, plus 2 times our L ligands. Here, we have carbonyl as our 2 L ligands. So that's 2 times 2. So here this comes out to 10 plus 2 plus 4. So, in this case, palladium is following a 16 electron rule.

Now that we've seen this one, we'll move on in the next video to the second example. This one may not be what you think it is. Think of what kind of ligand is our en. What is that abbreviation for? That's going to play a role in terms of calculating our electron count for this particular complex. So come back and see how I approach example 2.