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Ch.6 - Alkyl Halides; Nucleophilic Substitution
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
Chapter 6, Problem 6b

For each pair of compounds, predict which compound has the higher boiling point. Check [TABLE 6-2] to see if your prediction was right; then explain why that compound has the higher boiling point.
b. isopropyl chloride and tert-butyl bromide

Verified step by step guidance
1
Identify the functional groups and molecular structures of each compound. Isopropyl chloride is an alkyl halide with a chlorine atom attached to an isopropyl group, while tert-butyl bromide is an alkyl halide with a bromine atom attached to a tert-butyl group.
Consider the molecular weight of each compound. Bromine is heavier than chlorine, which generally contributes to a higher boiling point due to increased van der Waals forces.
Evaluate the branching in the carbon chain. Tert-butyl bromide has more branching compared to isopropyl chloride, which can affect boiling point by reducing surface area and intermolecular forces.
Analyze the electronegativity and polarizability of the halogens. Bromine is less electronegative but more polarizable than chlorine, which can lead to stronger intermolecular forces and a higher boiling point.
Compare the intermolecular forces present in each compound. Consider dipole-dipole interactions and van der Waals forces, which are influenced by the size and polarizability of the halogen atoms.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Intermolecular Forces

Intermolecular forces are the forces that hold molecules together, affecting properties like boiling points. The stronger the intermolecular forces, such as hydrogen bonding, dipole-dipole interactions, and van der Waals forces, the higher the boiling point. In this context, understanding the type and strength of these forces in isopropyl chloride and tert-butyl bromide is crucial.
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How Van der Waals forces work.

Molecular Structure and Polarity

The molecular structure and polarity of a compound influence its boiling point. Polar molecules, which have uneven distribution of electron density, typically exhibit stronger dipole-dipole interactions, leading to higher boiling points. Analyzing the structure of isopropyl chloride and tert-butyl bromide helps determine their polarity and predict boiling points.
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Molecular Polarity

Halogen Influence on Boiling Point

Halogens, such as chlorine and bromine, impact boiling points due to their size and electronegativity. Bromine, being larger and less electronegative than chlorine, can lead to stronger van der Waals forces in tert-butyl bromide compared to isopropyl chloride. This concept helps explain why tert-butyl bromide might have a higher boiling point.
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Related Practice
Textbook Question

For each pair of compounds, predict which compound has the higher boiling point. Check [TABLE 6-2] to see if your prediction was right; then explain why that compound has the higher boiling point.

c. 1-bromobutane and 1-chlorobutane

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Textbook Question

Show how you might use SN2 reactions to convert 1-chlorobutane into the following compounds.

a. butan-1-ol

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Textbook Question

Show how you might use SN2 reactions to convert 1-chlorobutane into the following compounds.

b. 1-fluorobutane

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Textbook Question

The light-initiated reaction of 2,3-dimethylbut-2-ene with N-bromosuccinimide (NBS) gives two products:

a. Give a mechanism for this reaction, showing how the two products arise as a ­consequence of the resonance-stabilized intermediate.

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Textbook Question

For each pair of compounds, predict which compound has the higher boiling point. Check [TABLE 6-2] to see if your prediction was right; then explain why that compound has the higher boiling point.

a. isopropyl bromide and n-butyl bromide

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Textbook Question

Under appropriate conditions, (S)-1-bromo-1-fluoroethane reacts with sodium methoxide to give pure (S)-1-fluoro-1-methoxyethane.

a. Why is bromide rather than fluoride replaced?

b. Draw perspective structures (as shown on the previous page for 2-bromobutane) for the starting material, the transition state, and the product.

c. Does the product show retention or inversion of configuration? d. Is this result consistent with reaction by the SN2 mechanism?

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