Now what I'm going to do is I'm going to give you guys this problem that is actually really easy, but I'm still going to give it to you guys just as a free response. Go ahead and try to solve which one would be the more acidic, the right or the left. So go ahead and pause the video and tell me. So the answer is obviously this one would be more acidic. Okay? Because this one actually meets all three criteria. It has some electronegative elements that are not attached. It actually has 4 fluorines. It has a lot of them, 4, and they're all really close. They're all exactly on the alcohol. So this is an example of just a really easy question that you could get.
Now some of you guys might also be asking this, but Johnny, how about if my professor gives me one but not the other and if he switches them up? For example, what if on one of them, one of the acids has a bromine but then the other one has 2 bromines but then the other one has one fluorine. How do I know which one is better? And my answer to that is that professors are never that mean. So what they're going to do is because the only way to figure that out would actually be to do math and to actually do empirical calculations. So you're never going to have to worry about, oh, this one has more but this one is closer, stuff like that. Unless it's really obvious, like the one I gave you up there was obvious because it was way too far away. But if it was like you can't really tell the difference, you wouldn't get that kind of question. It's always going to be just these three things pulled together. So for example, one of them, let's say this was an alcohol, one of them could be like having 1 chlorine and then the other alcohol could be like having 1 fluorine. And then you just have to pick the difference between those 2. Okay. It wouldn't be like that you're having to pick the difference between 1 fluorine and 2 chlorines because that would be way too hard. Alright. So hopefully that makes sense to you guys. Let's go ahead and move on.
