So here it says to determine the final product in the following reaction. Alright. So, we have to undergo reductive elimination. Up to this point, we've added our alkene group, which was our R1 group. We've added this alkene group which is our R2 groups. Now, we have to get them to combine together. Alright. So, we're going to say that our R1 group, which is this group up here, breaks off from my transition metal complex and combines with this carbon here. At the same time, this bond here breaks and goes back to the palladium. So, we wind up getting this structure with that alkene group attached to where the palladium was once attached. And we do it this way in order to maintain or retain our stereochemistry. This alkene here had an E configuration. And by adding the R1 group up here, it maintains that E configuration. We also have the regeneration of our palladium catalyst. Those will be our 2 final products.

Now, what we need to realize here is that reduction is seen as the gaining of electrons and a decrease in an element's oxidation number. Now, when the 2 X-type ligands, because remember, the R1 and R2 are acting like ligands but more specifically X-type ligands, when they're lost, the oxidation state of the transition metal decreases by 2. Remember, this bond here breaks and those 2 electrons go back to the palladium. Therefore, the oxidation state decreases by 2 because you gain those 2 electrons back. Now, at the same time, the formation of a conjugated product, our conjugated product here, allows for the unstable catalysts to be regenerated. So here we just regenerated it. It's great that we made something that's more conjugated, therefore, we made a very stable product. But we wound up regenerating our transition metal catalyst which is going to want to go through another wave or another cycle of a cross-coupling reaction in order to get this transition metal back within the 18 or 16 electron count. Okay. So these are our driving forces. We want to make something more stable as a product, but then the transition metal wants to get to 18 or 16 electrons. Those two forces are what pushes and propels these typical cross-coupling reactions.