So this one wasn't so bad either. The chiral center is right here on the side, and one thing I just want to show you guys is that this really is a chiral center. Obviously, the two substituents are different from each other. You guys might have been confused by the ring. But notice that one side of the ring is different from the other. For example, on the blue side, it takes me two carbons to get to the double bond, whereas on the green side, I immediately have a double bond right when I leave that chiral center. That means that that ring is not perfectly symmetrical, so both sides of this ring do count as different groups.
So now we just have to do priorities. My number one priority is going to be the nitrogen. It has to be because nitrogen is heavier than carbon. But notice that once again, I'm going to have a three-way tie between atoms. I have a blue carbon, a red carbon, and a green carbon. How did you guys figure this out? Hopefully, you guys used playoffs. For the green carbon, we're going to use the "double bond counts twice" rule. So I'm going to say it's attached to a carbon, a carbon, and an H. The red carbon is attached to one carbon and two Hs. Those Hs are right here. And the blue one is a methyl. So we know that methyls are only attached to hydrogen, and those are your priorities right there. Our priorities were that green was my 2, red is my 3, and now in this case, my methyl group is actually my 4. Hydrogen doesn't always have to be your 4th, meaning let me say that back. Let me say that the other way. Your 4th doesn't necessarily need to be hydrogen. If you don't have any hydrogens by themselves on your chiral center, you're just going to go with whichever group is the biggest loser. That's your number 4. If you happen to have a hydrogen, then of course, that's going to be your biggest loser because there's nothing smaller than it. Let's move on to the next step.
