Predict the compound in each pair that will undergo the SN2 reaction faster.
(a) or
(b) or
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1
Identify the factors affecting SN2 reactions: steric hindrance and leaving group ability.
For part (a), compare the steric hindrance of the two compounds. The compound with the bromine on a primary carbon will undergo SN2 faster than the one on a tertiary carbon.
For part (b), compare the leaving group ability. Iodine is a better leaving group than chlorine, so the compound with iodine will undergo SN2 faster.
Consider the structure of the compounds: primary, secondary, or tertiary. Primary carbons are less hindered and more favorable for SN2 reactions.
Evaluate the leaving group: Iodine (I) is a better leaving group than bromine (Br) and chlorine (Cl), which is better than fluorine (F).
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