Lead ions can be precipitated using a solution of bromide ions: Pb²⁺(aq) + 2 Cl^–(aq) → PbCl₂(s)     ΔH°_f = –336.0 kJ/mol
Calculate ΔH for the formation of 5.15 g PbCl₂.

• A. –0.516 kJ
• B. –4.17 kJ
• C. –6.22 kJ
• D. –10.19 kJ

Answer: (C)