Determine if the compound of BCl 2 F is polar or nonpolar.

Determine if the compound of BCl2f is polar or nonpolar. Alright. So boron's in group 3 a. Chlorine is in group 7 a, and there's 2 of them, and Fluorine is also in group 7 a. So that's gonna give me 24 total valence electrons. So now, I'm gonna place the least electronegative one in the center which is boron. It's gonna form single bonds to these elements. We place enough electrons around them, so they're following the octet rule. Doing this means that we use all 24 of our valence electrons. So there is no more electrons that we can place anywhere. If If we take a look here, although the central element has no lone pairs, all the surrounding elements are not the same. We have chlorines and fluorine as surrounding elements. Remember, to be a perfect shape, the central element have needs to have 0 lone pairs and all the surrounding elements must be the same. Because of that, this is not a perfect shape and therefore the molecule itself or compound itself is polar.