Complete the following hydrohalogenation reaction. Here we have our alkene reacting with HCl. What we do first is we look to see what kind of double bonded carbons we have. The one on the left is making 4 bonds, so it has no hydrogens. The one on the right is making 3 bonds that we see, so it has 1 hydrogen. Since the two double-bonded carbons have different numbers of hydrogens, we are going to use Markovnikov's rule to determine where the H and the Cl will go. Following Markovnikov's rule, it states that the hydrogen will go to the double-bonded carbon with more hydrogens, so it would go here. Of course, the hydrogen that was originally there is still there, and then the chlorine would go to the double bonded carbon with fewer hydrogens. So it would go here.
This will represent the alkyl halide product formed from the hydrohalogenation between our reactants. Now remember, your hydrogens when they are connected to carbon are invisible, so you could erase them, and this would be our full skeletal formula for our product.