For each of the following compounds, indicate whether or not it can exist as cis–trans stereoisomers. If it can exist as the two isomers, draw both as a condensed structure. (a) H₂C=CHCH₂CH₃

Welcome back. Everyone can the following structure exist as cist trans stereo isomers if it can through both stereo isomers showing only the bonds from branching and were given our structure. Whenever we consider cran isomerism in L Keynes, the best idea is to begin by drawing the carbon carbon double bond. And we can notice that our structure has that double bond. The left carbon has two muscle groups attached to it. So we're going to draw one muscle group and then the other, the other double bonded carbon has an ethyl substituent given to us in pres. So we can just draw ch two followed by CH three. And then were also given the be substituent with a total of four carbon atoms ch two, three times. And then see each three. Now can this structure exhibit c trans stereo isomerism? Well, we have to consider the double bonded carbons. And the work first condition that we want to understand is simply to make sure that every double bonded carbon has two different substi what we notice is that carbon number one, which is basically the first double bonded carbon contains two exactly same methyl substitutions. We can state that they are the same. And because they are the same, we are going to conclude that this structure cannot exhibit c trans stereoisomerism. And that be our final answer. The given L kin doesn't contain such trans isomers because one of the double bonded carbons has two exactly same. Substi Thank you for watching.