How many grams of HNO 3 are required to completely neutralize 110.0 mL of 0.770 M LiOH?

Here it says how many grams of nitric acid are required to neutralize 110 ml of 0.770 molar lithium hydroxide. So here we have our equation, and what we need to realize is the equation is already balanced. It's a one to one relationship across the board. What we're gonna say next is, remember, of means multiply, and volume of molarity can help me find moles. I'm gonna take the ml's and change them into liters. Remember, molarity is moles over liters, so this is point 770 moles of lithium hydroxide per 1 liter. Now that I have the moles of lithium hydroxide, I can do a mole to mole comparison to find the moles of nitric acid. So moles of lithium hydroxide go on the bottom, moles of nitric acid go on top. And according to my balanced equation, for every one mole of nitric acid, I have 1 mole of lithium hydroxide. Now since I have the moles of nitric acid, I can simply convert those moles into grams to get my final answer. So one mole of nitric acid weighs 63.018 grams. Remember, that's the mass of the 1 hydrogen, the 1 nitrogen, and the 3 oxygens. So this comes up to being 5.3 4 grams of nitric acid. So this would be my final answer.