Draw the condensed structural or line-angle formula if cyclic, for each of the following: (14.5) d. ethylmethylammonium bromide

Welcome back, everyone, write the condensed formula of methyl crop ammonium chloride. First of all, let's understand that we are going to write the condensed formula or an ammonium salt because it says ammonium chloride, right? And essentially, we can begin by drawing a bottom line structure. This is one of the easiest ways to identify the condensed formula. So how do we do that? Well, first of all, we're going to draw nitrogen, then we understand that nitrogen has two alky substitutions. One of them is a metal substituent ch three and the other is a prop substituent which is a three member chain. So simply speaking ch two ch two ch three, right. So we can represent that by a solid line, a metal group and then one, two and three carbon atoms. So we have a methyl substituent and then a prop substituent. And now it says ammonium chloride. Now, what does that mean? Well, we have already discussed that this is a salt, there is a chloride anion which is negatively charged. We can recall that from general chemistry. And now if we have a negatively charged ion, then the other one must be positively charged right. So from here, what we essentially want to do is first of all, add hydrogen to nitrogen. Why is that? Well, if we have two alkyl groups, right, there must be an additional hydrogen to form a total of three bonds and a long pair on nitrogen. In that case, it is neutral. But if we have an ammonium salt, similarly to NH four plus nitrogen uses its long pair of electrons to form the fourth bond. And this is exactly what we want to do. We want to proton data to form that positive charge. So we want to add an extra hydrogen. Therefore, there would be two hydrogen atoms bonded to nitrogen. We can essentially state NH two which gives nitrogen a positive charge. And now we want to isolate these two. Specifically, we want to put the cion in square brackets which isolates it from the anion. And from here, we can draw the condensed formula. So we will just begin from left to right. We will begin with C three. Let's recall that the condensed formula is simply a one align text which represents all of the atoms from left to right or right to left. So we have CH three followed by NH two, followed by CH two. This is the beginning of the prop substituent, followed by another C two. And finally see three, we can put square brackets around our cion and finish with the chloride anion cl minus. This represents ionic bonding and we have successfully determined the condensed formula for this structure. Thank you for watching.