How many O atoms of mass 15.99 amu are in 15.99 g of oxygen?

Verified step by step guidance

1. Identify the type of oxygen atoms in the problem. Here, the mass of an oxygen atom is given as 15.99 amu, which is approximately the mass of a single oxygen atom (O).
2. Use Avogadro's number to relate the mass of a mole of atoms to the number of atoms. Avogadro's number is approximately 6.022 x 10^23 atoms/mol.
3. Recognize that the molar mass of oxygen (O) is approximately 16.00 g/mol, which is very close to the given mass of 15.99 g.
4. Calculate the number of moles of oxygen in 15.99 g by dividing the mass of the sample by the molar mass of oxygen: $\text{moles of O}=\frac{15.99\text{ g}}{16.00\text{ g/mol}}$.
5. Multiply the number of moles of oxygen by Avogadro's number to find the number of oxygen atoms: $\text{number of O atoms}=\text{moles of O}\times 6.022\times {10}^{23}\text{ atoms/mol}$.

Key Concepts

Atomic Mass Unit (amu)

An atomic mass unit (amu) is a standard unit of mass that quantifies mass on an atomic or molecular scale. It is defined as one twelfth of the mass of a carbon-12 atom, approximately 1.66 x 10^-27 kg. In the context of the question, the mass of oxygen is given as 15.99 amu, which indicates the mass of a single oxygen atom.

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). For oxygen, the molar mass is approximately 16 g/mol, which means that one mole of oxygen atoms weighs about 16 grams. This concept is crucial for converting between grams and moles, allowing us to determine the number of atoms in a given mass of oxygen.

Avogadro's Number

Avogadro's number, approximately 6.022 x 10^23, is the number of atoms, ions, or molecules in one mole of a substance. This constant is essential for converting moles to the number of individual particles. In the context of the question, it allows us to calculate how many oxygen atoms are present in 15.99 grams of oxygen by first determining the number of moles and then multiplying by Avogadro's number.