Determine the elimination product form in the following reaction. Another name for a dehydration reaction is an elimination reaction. Here, we have alcohol reacting with sulfuric acid, so we know we're trying to create an alkene at the end. Here is our carbon, our alcohol carbon with its OH, and here are the neighboring carbons. This neighboring carbon here is making 2 bonds, so it has 2 hydrogens. This neighboring carbon here makes 2 bonds, so it has 2 hydrogens we don't see.
In this process, we're going to lose water, losing an OH from the alcohol carbon, and losing an H from one of its neighboring carbons. Here, I decide to lose it from this side. But it could equally happen on the other side because those two neighboring carbons are the same. They both have 2 hydrogens. So, when we lose water, that's going to force those 2 carbons to make a double bond with one another to continue to make 4 bonds. Our alkene would look like this, and this would be cyclohexene. This would be our elimination or dehydration product.