Here it says, determine the systematic name of the following alkane. Our job is first to find the longest carbon chain, which represents our parent chain. We're utilizing steps 1 to 6. Remember, we're utilizing the rules that we learned in terms of naming alkanes with substituents. You have to watch those videos, make sure you go back and take a look at those 6 steps. So here, 1, 2, 3, 4, 5, 6, 7, 8, 9. 9 seems to be the longest chain that we can have in terms of this alkane. So that is our parent chain. We'll highlight it for ourselves.
Now remember, we number from the end closest to a substituent. Here we have a 3 carbon substituent, a 1 carbon substituent, and bromine. 1, 2, 3, 4 to get to this 3 carbon substituent. Or 1, 2, 3 to get to the bromine substituent. We number it from the end closest to a substituent, so we're going to number it from the right side. So, 1, 2, 3, 4, 5, 6, 7, 8, 9. 9 carbons means that our alkane is nonane. Now, about our substituents. A 3 carbon substituent with the bond on the middle, carbon means that this is isopropyl. A one carbon substituent would be methyl, and then bromine is termed bromo.
Remember we basically name, we number these for their location, and we write them alphabetically. B comes before I, I comes before M. So we start out with 3-bromo-6-isopropyl-5-methyl nonane. This would be the name of this particular alkane compound. Here we have the introduction of our halogen bromine group, which is listed as bromo.