A woman's father has ornithine transcarbamylase deficien...

Question

A woman's father has ornithine transcarbamylase deficiency (OTD), an X-linked recessive disorder producing mental deterioration if not properly treated. The woman's mother is homozygous for the wild-type allele.

What is the woman's genotype? (Use D to represent the dominant allele and d to represent the recessive allele.)

Accepted Answer

Hey, everyone. Let's take a look at this question together if the father has an excellent disease and the mother is not a carrier, which of the following is true. Is it answer choice. A, the disease will show up in their daughters. Answer choice. B, the disease will show up in their sons. Answer choice. C, the disease may show up in their grandsons or answer choice. D all options are correct. Let's work this problem out together to try to figure out which of the following answer choices is the correct answer. So we have this father that we know as the X linked disease. So we will represent the father by his X N Y chromosome and we will put that mut on his X chromosome since we know that it is an X linked disease. And we have the mother which we know has two X chromosomes and is not a carrier. So to indicate that she is not a carrier, we're going to put an N on her two X chromosomes, which the N will be used to represent that non mutant A leo and the M will be used to represent the mutant A which the father has because he has that excellent disease. And so let's go ahead and set up 100 square cross between the father and the mother in order to get more information about what their offspring might look like. So now that we have this punt square cross between the mother and father, we are able to see what their offspring might look like. And we are able to determine that the disease may show up in their grandsons. Which means that answer choice C the disease may show up in their grandsons is the correct answer. And we know that this is the correct answer because the mule only shows up in the daughters of this cross and not in the sons. And we also know that this means that the daughters from this cross are carriers and will pass on that X chromosome to their son, which means that the disease may show up in their grandsons, which is answer choice C making it a true statement. And the correct answer to the question because answer choice A which says the disease will show up in their daughters is incorrect. And answer choice B which says the disease will show up in their sons is also incorrect. Since the disease will not show up in their daughters or sons and their daughters will be carriers for that link disease. So answer choice C is the correct answer. I hope you found this video to be helpful. Thank you and goodbye.

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