A geneticist crosses a pure-breeding strain of peas prod...

Question

A geneticist crosses a pure-breeding strain of peas producing yellow, wrinkled seeds with one that is pure-breeding for green, round seeds.

Use a Punnett square to predict the F₂ progeny that would be expected if the F₁ are allowed to self-fertilize.

Accepted Answer

Hello, everyone and welcome to today's video. So if we cross to heterosexual parents with the same genotype as we see here, what is the probability of producing a progeny that has recessive phenotype for all three traits? Well, remember if they're going to have recessive phenotype, these recessive phenotype are only yielded by recessive genotype. So when we look at our punnett squares, we need to look for the recessive genotype and these are going to be the correct ones. Well, here we have a very important shortcut that we're going to be using since we're told that both parents are heterosexuals for all Jenna types. As we see here, if we cross the B genotype or the C genotype or the D genotype of both parents were going to obtain the same probability of yielding recessive phenotype for all three. So what we can do instead of having to do all that work is due upon it square for a single genotype. In this case, the B genotype. And once we make that cross, as we see here, we're going to see that the probability of obtaining recessive phenotype is 1/4. Now, if we did the same thing for the C genotype or for the D genotype, we will still get 1/4 for all of them because they're all hetero sickos were crossing a hetero sickos genotype without hetero sickos genotype. So all we need to do really to find the total probability is multiply These three probabilities. And we're going to obtain the total probability of obtaining recessive phenotype is for all three trades is going to be 1/64. So the correct answer choice here is going to be answer choice. EI really hope this video helped you and I hope to see you on the next one.

A geneticist crosses a pure-breeding strain of peas producing yellow, wrinkled seeds with one that is pure-breeding for green, round seeds.

Use a Punnett square to predict the F₂ progeny that would be expected if the F₁ are allowed to self-fertilize.

Key Concepts

Mendelian Genetics

Punnett Square

Genotype and Phenotype

Watch next

A geneticist crosses a pure-breeding strain of peas producing yellow, wrinkled seeds with one that is pure-breeding for green, round seeds.Use a Punnett square to predict the F₂ progeny that would be expected if the F₁ are allowed to self-fertilize.

Key Concepts

Mendelian Genetics

Punnett Square

Genotype and Phenotype

Watch next

A geneticist crosses a pure-breeding strain of peas producing yellow, wrinkled seeds with one that is pure-breeding for green, round seeds.

Use a Punnett square to predict the F₂ progeny that would be expected if the F₁ are allowed to self-fertilize.