In the mouse, Mus musculus, survival in agricultural fields that ...

Question

In the mouse, Mus musculus, survival in agricultural fields that are regularly sprayed with a herbicide is determined by the genotype for a detoxification enzyme encoded by a gene with two alleles, F and S. The relative fitness values for the genotypes are

Genotype Relative fitness
FF 0.72
FS 1.00
SS 0.45

Why will this pattern of natural selection result in a stable equilibrium of frequencies of F and S?

Accepted Answer

Hello, everyone and welcome to today's video. So in a population of fish genotypes for the homozygote dominant, heterozygous and homozygote recessive have relative fitness values of 0.72 0. one respectively. Based on this information, which genotype has the greatest reproductive success success. As answer choice. A we have the homo Zygo dominant as answer choice. B we have the hetero as answer choice C we have the homo Zygo recessive and as answer choice D we have, they all have equal reproductive success. Well, there is something that we need to understand about this problem before we jump into our answer choices. So the greater the relative fitness, the greater the reproductive success. So all we have to do really is compare their relative thinness values of each genotype and then decide which one is highest and that will be the greatest reproductive success when comparing them. So we are told in the problem that the, we're told that the hetero has a relative thinness value of 0.36. And then we're told that the homo cycles recessive has a relative fitness value of one. So the highest relative relative thinness value is going to be one or the Homo Zygo recessive answer choice C So we're going to highlight answer choice E which is lower case A A or.

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