In studies of recombination between mutants 1 and 2 from Problem ...

Question

In studies of recombination between mutants 1 and 2 from Problem 21, the results shown in the following table were obtained.

Strain Dilution Plaques Phenotypes
E. coli B 10⁻⁷ 4 r
E. coli K12 10⁻² 8 +

When mutant 6 was tested for recombination with mutant 1, the data were the same as those shown above for strain B, but not for K12. The researcher lost the K12 data, but remembered that recombination was ten times more frequent than when mutants 1 and 2 were tested. What were the lost values (dilution and plaque numbers)?

Accepted Answer

Everyone. Let's take a look at this question. Together in mapping experiments, what does the frequency of recombination imply? Let's recall what we've learned about mapping experiments and what the frequency of recombination implies. So, we know in genetics that re combination frequency has to do with that frequency that a single almost almost crossover the curves and this is between two genes, meaning what is that percentage that that crossover between the two genes will occur during mitosis. But when we're dealing with genetic mapping here, we can see a gene that has two mutations here and here and so the frequency of recombination provides us with an estimate of this distance here between those two mutations, which means that answer, Choice B is the correct answer. Because during those mapping experiments, where we can see a gene that has two mutations, we can figure out an estimate of the distance between the two genes to figure out that frequency of recombination. Because we know that recombination frequency is the probability that a single chromosome will crossover will occur between two genes. So answer Choice B is the correct answer. I hope you found this video to be helpful. Thank you and goodbye

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