Red–green color blindness is a relatively common conditi...

Question

Red–green color blindness is a relatively common condition found in about 8% of males in the general population. From this, population, biologists estimate that 8% is the frequency of X chromosomes carrying a mutation of the gene encoding red and green color vision. Based on this frequency, determine the approximate frequency with which you would expect females to have red–green color blindness. Explain your reasoning.

Accepted Answer

Hi, everyone. Let's take a look at this practice problem together. An X linked recessive A lil is the cause of a common form of human red green color blindness. Which of the following statements about inheritance probabilities is incorrect. The answer options are a, there is a 0% chance that two parents who are colorblind will give birth to unaffected Children. Option B if the father is unaffected and the mother has a hidden recessive, a little 50% of the sons will be color blind. Option C if the father is unaffected and the mother has a hidden recessive, a little 50% of the daughters will be colorblind and option D, none of these. So if red green, color blindness is a, an excellent recessive disorder, that means an affected female would have homozygous recessive genotype and any affected male would carry the recessive a little. So let's use the letter R to represent the color blindness gene where capital R will represent the dominant a little and lower case R will represent the recessive a little. Let's look at the scenario in option A that both parents are colorblind. In option A, a male's genotype would therefore be X lowercase Y and the affected female genotype is homozygous recessive. In this cross, the punted square results are on the screen. So this is the result of option A, all Children to parents who are both color blind will also b colorblind. Therefore, option A is a true statement. There's 0% chance that two affected parents will give birth to unaffected Children. So option A is true and therefore not the incorrect statement. Now, let's consider the scenario and options B and C, the father is unaffected and therefore would have genotype X capital R Y and the female with the hidden recessive A lil means that she has a heterozygous genotype X capital R X lowercase R. The results of this cross are on the screen in a punt square of the mill offspring of this cross. one is unaffected and has the dominant A lil and the other male is affected with the recessive A lil. Therefore, 50% of the male offspring will be color blind. So, option B is also a true statement and therefore, is not the incorrect statement. If we look at the female offspring and analyze the punt square one is homozygous dominant and the other is heterozygous. Therefore, both are not affected by color blindness. This means that the incorrect statement and our correct answer is option C if the father is unaffected and the mother has a hidden recessive, a little 50% of the daughters will be colorblind. All right, everyone. I hope you found this helpful and I'll see you soon for the next practice problem.

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