Mendel crossed peas having round seeds and yellow cotyledons (see...

Question

Mendel crossed peas having round seeds and yellow cotyledons (seed leaves) with peas having wrinkled seeds and green cotyledons. All the F₁ plants had round seeds with yellow cotyledons. Diagram this cross through the F₂ generation, using both the Punnett square and forked-line, or branch diagram, methods.

Accepted Answer

Hey everyone, let's take a look at this question. Together. If a yellow and round P. Is crossed with a green and round P. Using the punnett square, what is the probability of producing a yellow and wrinkled pea in the F. One generation. Let's recall what we've learned about how to set up a punnett square to try to figure out how the yellow and round P. Would be cross with the green and round P. To figure out the probability of producing that yellow and wrinkled P. So we know that when we're dealing with the yellow and wrinkled pea, yellow being this be big G. Little G. And green being this small G. Small G. That means for yellow, we would have to have a big G. Big G. Or that big G. Little G. So either a homicide is dominant or a hetero sickness. And then for the round or wrinkled pea, we see that for the roundness of the P. Is dominant. So to have that wrinkled pea, we would have to have a homicide recessive or little W. Little. So what we're looking for is either big G. Big G. Little W. Little W. Or big G. Little G. Little W. Little W. Let's go ahead and set up the punnett square to try to figure out how the two will cross in the F. One generation. So here you can see how the punnett square would look when we're crossing both of these and let's go ahead and fill out the rest of the punnett square to see the probability of producing that yellow and wrinkled pea. So in this case, since we cannot have a homicide is dominant of Big G, Big G, we can only have the heterocyclic of big G, little G. And little W. Little W. And so out of 16. We only experience that twice which is here and here. So that means we have two out of 16 or one out of eight. Give us that yellow and wrinkled pea in this F. One generation. That means that answer choice D. Is the correct answer based on the punnett square of crossing that yellow and round P. With that green and round P. To figure out the probability of producing a yellow and wrinkled P. I hope you found this video to be helpful. Thank you and goodbye.

Key Concepts

Mendelian Genetics

Punnett Square

Forked-Line (Branch Diagram)

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