Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
2. Mendel's Laws of Inheritance
Sex-Linked Genes
2:29 minutes
Problem 33b
Textbook Question
Textbook QuestionForm a small discussion group and decide on the most likely genetic explanation for each of the following situations;
A man who has red–green color blindness and a woman who has complete color vision have a son with red–green color blindness. What are the genotypes of these three people, and how do you explain the color blindness of the son?
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
X-Linked Inheritance
Red-green color blindness is an X-linked recessive trait, meaning the gene responsible for this condition is located on the X chromosome. Males, having one X and one Y chromosome, express the trait if their single X carries the allele for color blindness. Females, with two X chromosomes, must have the allele on both Xs to express the trait, making them less likely to be color blind.
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X-Inactivation
Genotype of the Individuals
In this scenario, the man with red-green color blindness has the genotype X^cY, where X^c represents the X chromosome with the color blindness allele. The woman with complete color vision can be either X^cX (carrier) or X^NX^N (homozygous normal). Their son, who has red-green color blindness, must inherit the X^c from his mother and the Y from his father, resulting in the genotype X^cY.
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Gamete Genotypes
Punnett Square Analysis
A Punnett square can be used to predict the genotypes of offspring based on the parents' genotypes. In this case, if the mother is a carrier (X^cX^N), the Punnett square will show a 50% chance of the son being color blind (X^cY) and a 50% chance of having normal vision (X^NY). This tool helps visualize the inheritance patterns and probabilities of traits in offspring.
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Chi Square Analysis
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