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Ch.14 - Chemical Kinetics

Chapter 14, Problem 25b

(b) The reaction 2 NO1g2 + Cl21g2¡2 NOCl1g2 is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate of 56 torr/min, what is the rate of change of the total pressure of the vessel?

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Hi everyone for this problem, we are given the falling reaction and told it takes place in a closed vessel, calculate the containers rate of change of total pressure when the rate of the partial pressure of S. I. Gas decreases by 67 tour per minute. Okay, so our goal here is to calculate the containers rate of change of total pressure. So we're going to need to write out a rate expression here to be able to do that. And so let's write out rewrite our equation and then we'll write out the rate expression. So what are rate expression is it shows our change and partial pressure over change in time. And so because we are reactant are decreasing, they're going to have a negative sign. And we're forming products. Our product is going to have a positive sign. So that change is going to look like our change in partial pressure for our first reactant over a change in time is equal to negative change and partial pressure of our second reactant. And this is going to be over change in time. But we're going to be dividing by two because we have two moles of it. And this is going to equal our change in partial pressure over over time for our product. And this is positive because we're forming product. Okay, so we have one mole of S. I. Two moles of F. Two and one mole of S. I. F. Four. Okay, so now that we have our rate expression, we can go ahead and plug in the values for our partial pressures. So in the problem we're told that the rate of partial pressure of S. I. Decreases by 67 Tour per minute. So this is going to show up as negative 67 Tour for a minute Is equal to our change for our second reactant. So we're going to take our 67 tour per minute and divide it by two because we have two moles. Okay, and so we're going to get negative 33. tour per minute Is equal to our product, and it's going to be positive 67 Tour per minute. Okay. So based off of this written rate expression, the problem asked us to calculate the rate of change of total pressure. So our change in total pressure Over change in time is going to equal the sum of these values. So we're going to add them all up. So negative 67 tour per minute Plus -33.5 Tour per minute Plus positive 67 tour per minute. Okay, So when we take this some we're going to get our change. Our rate of change of total pressure Is going to equal negative Tour per minute. And that is the answer to this problem. That's it. I hope this was helpful