Multiple ChoiceCalculate Kc for: C(s) + ½ O2(g) + H2(g) ⇌ ½ CH3OH(g) + ½ CO(g) Kc = ?Given the following reactions:4 C(s) + 2 O2(g) ⇌ 4 CO(g) Kp = 2.11 x 1043CH3OH(g) + H2O(g) ⇌ CO2(g) + 3 H2(g) Kp = 7.17 x 10–2CO(g) + H2O(g) ⇌ CO2(g) + H2(g) Kp = 2.00 x 103240views3comments
Textbook QuestionConsider the reactions and their respective equilibriumconstants:NO(g) + 1/2 Br (g) ⇌ NOBr(g) K = 5.32NO(g) ⇌ N2(g) + O2(g) Kp = 2.1*10^30Use these reactions and their equilibrium constants to predictthe equilibrium constant for the following reaction: N2(g) + O2(g) + Br2(g) ⇌ 2NOBr(g)111views
Textbook QuestionCalculate the value of the equilibrium constant for the reaction 4 NH31g2 + 3 O21g2 ∆ 2 N21g2 + 6 H2O1g2given the following equilibrium constants at a certain temperature.2 H21g2 + O21g2 ∆ 2 H2O1g2 Kc = 3.2 * 1081N21g2 + 3 H21g2 ∆ 2 NH31g2 Kc = 3.5 * 108125views
Textbook QuestionConsider the equilibrium N21g2 + O21g2 + Br21g2 Δ 2 NOBr1g2 Calculate the equilibrium constant Kp for this reaction, given the following information (at 298 K): 2 NO1g2 + Br21g2Δ2 NOBr1g2 Kc = 2.0 2 NO1g2ΔN21g2 + O21g2 Kc = 2.1 * 1030986views
Textbook QuestionCarbon monoxide replaces oxygen in oxygenated hemoglobin according to the reaction: HbO2(aq) + CO(aq) ⇌ HbCO(aq) + O2(aq) a. Use the reactions and associated equilibrium constants at body temperature given here to find the equilibrium con- stant for the reaction just shown. Hb(aq) + O2(aq) ⇌ HbO2(aq) Kc = 1.8 Hb(aq) + CO(aq) ⇌ HbCO(aq) Kc = 3062554views
Textbook QuestionThe following equilibria were measured at 823 K: CoO1s2 + H21g2 ΔCo1s2 + H2O1g2 Kc = 67 H21g2 + CO21g2 ΔCO1g2 + H2O1g2 Kc = 0.14 (a) Use these equilibria to calculate the equilibrium constant, Kc, for the reaction CoO1s2 + CO1g2ΔCo1s2 + CO21g2 at 823 K.899views