if-75-ml-of-a-solution-made-by-dissolving-10-0-g-of-ba-oh-2-ksp-5-0x10-3-in-300-

Question

If 75 mL of a solution made by dissolving 10.0 g of Ba(OH)₂(K_sp = 5.0×10^–3) in 300 mL of water was added to each of the beakers below, which beaker will a precipitate form? What is the identity of the precipitates that formed?

Four beakers labeled (i) to (iv) with different solutions for a chemistry experiment.

Accepted Answer

Only beaker (iii) will form a precipitate. The precipitate that will form is Ba(OH)₂

Answer

Only beaker (iv) will form a precipitate. The precipitate that will form is Ba(OH)₂

Answer

Beaker (i) and beaker (ii) will form a precipitate. The precipitate that will form is Ba(OH)₂ and NaOH

Answer

Beaker (iii) and beaker (iv) will form a precipitate. The precipitate that will form is Ba(OH)₂ and BaBr₂