the-spin-only-magnetic-moment-of-a-transition-metal-complex-in-bohr-magnetons-bm

Question

The spin-only magnetic moment of a transition metal complex in Bohr magnetons (BM) is calculated as $\sqrt{n (n + 2)}$ , where n is the number of unpaired electrons. It is proportional to the amount of paramagnetism in the metal. What is the spin-only magnetic moment of Mn³⁺, a first-series transition metal, when it forms an octahedral complex with strong and weak field ligands? Can the magnetic moment distinguish between the electron configurations of Mn³⁺ with a weak-field and strong-field ligand?

Accepted Answer

The spin-only magnetic moment of Mn³⁺ when it forms an octahedral complex with a strong field ligand is 2.83 and with weak field ligands is 4.90. It can distinguish between the two electron configurations.

Answer

The spin-only magnetic moment of Mn³⁺ when it forms an octahedral complex with a strong field ligand is 4.90 and with weak field ligands is 2.83. It can distinguish between the two electron configurations.

Answer

The spin-only magnetic moment of Mn³⁺ when it forms an octahedral complex with a strong field ligand is 3.87 and with weak field ligands is 3.87. It cannot distinguish between the two electron configurations.

Answer

The spin-only magnetic moment of Mn³⁺ when it forms an octahedral complex with a strong field ligand is 2.83 and with weak field ligands is 2.83. It cannot distinguish between the two electron configurations.

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